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2 years ago

PLS HELP AND DONT GET IT WRONG!

Mathematics

2 answers:

ivolga24 [154]2 years ago

8 0

$\frac{5(u^{-3})^2}{2u^8} =\frac{5u^{-6} }{2u^8} = \frac{5}{2} u^{-6-8} =\frac{5}{2} u^{-14} =\frac{5}{2u^{14} }$

Hope that helps!

Alex2 years ago

3 0

Answer:

$\frac{5}{2u14}$

Sry for answering again my answer was reported.

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