Question

PLS HELP AND DONT GET IT WRONG!

Answer 1

$\frac{5(u^{-3})^2}{2u^8} =\frac{5u^{-6} }{2u^8} = \frac{5}{2} u^{-6-8} =\frac{5}{2} u^{-14} =\frac{5}{2u^{14} }$

Hope that helps!

Answer 2

Answer:

$\frac{5}{2u14}$

Sry for answering again my answer was reported.