Answer:
14 and 20
Step-by-step explanation:
<u><em> Let x and y be two numbers where x < y</em></u><em>.</em>
We are given :
y - x = 6
y² - x² = 204
Then
y - x = 6
(y - x)(y + x) = 204
Then
y - x = 6
6 × (y + x) = 204
then
y - x = 6 (Equation 1)
y + x = 34 (Equation 2)
Then
(Equation 1) + (Equation 2) ⇒ 2y = 40 ⇒ y = 20
Now ,we substitute y by 20 in equation 1 :
y - x = 6
⇔ 20 - x = 6
⇔ 20 - 6 = x
⇔ x = 14
Answer:
The larger number is 
Step-by-step explanation:
Let larger number be 
We have

Answer:

or

Step-by-step explanation:
Hello!
Use the quadratic formula: 
First, let's convert our equation to standard form of a Quadratic: ax² + bx + c = 0
3x² = 80
3x² - 80 = 0
Note, thats the value of b will be 0, as there is no "bx"
Now, solve:
Plug in values
Simplify the radical (Discriminant)
Pull out perfect squares
Reduce factors
The solutions are 
Answer:
5
Step-by-step explanation: