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morpeh [17]
3 years ago
8

Find the discriminant of 5x^2+3x-5=0 for x

Mathematics
2 answers:
grandymaker [24]3 years ago
7 0

For this case we have that by definition, a quadratic equation is of the form:

ax ^ 2 + bx + c = 0

Its roots are given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

By definition, the discriminant is given by:

D = b ^ 2-4 (a) (c)

According to the given equation we have to:

a = 5\\b = 3\\c = -5

Substituting:

D = 3 ^ 2-4 (5) (- 5)\\D = 9 + 100\\D = 109

Answer:

The discriminant is 109

Marta_Voda [28]3 years ago
4 0
The discriminant is 109
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