2 years ago

HELPP WITH THESE THREE QUESTIONS PLEASE i got yall with 30 points for these three answers

Mathematics

1 answer:

kvv77 [185]2 years ago

5 0

I can't really explain it

see the picture

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I took an average of all of the numbers and its shows that he bus will be there about 8:20.25

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A = 1/2pl + B solve for p

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Read 2 more answers

Let X and Y denote the values of two stocks at the end of a five-year period. X is uniformly distributed on the interval (0, 12)

Paladinen [302]

Answer:

Cov (X,Y) = 6

Step-by-step explanation:

hello,

Cov(X,Y) = E(XY) - E(X)E(Y)

we must first find E(XY), E(X), and E(Y).

since X is uniformly distributed on the interval (0,12), then E(X) = 6.

next we find the joint density f(x,y) using the formula

$f(x,y) = g(y|x)f_{X}(x)$

$f_{X} (x) = \frac{1}{12} \ $for$\ 0$ this is because f is uniformly distributed on the the interval (0,12)

also since the conditional probability density of Y given X=x, is uniformly distributed on the interval [0,x], then

$g(y|x)=\frac{1}{x}$ for 0≤y≤x≤12

thus

$f(x,y)=\frac{1}{12x}$ .

hence,

$E(X,Y)= \int\limits^{12}_{x=0} \int\limits^x_{y=o} xy\frac{1}{12x} \,dy dx$

$E(X,Y)=\frac{!}{24} \int\limits^{12}_{x=0} x^2 \, dx = 24$

also,

$E(Y) = \int\limits^{12}_{x=0} \int\limits^x_{y=0} y\frac{1}{12x} \, dydx$

$E(Y)=\frac{1}{24}\int\limits^{12}_{x=0} {x} \, dx =3$

thus Cov(X,Y) = E(XY) - E(X)E(Y)

= 24 - (6)(3)

= 6

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4 years ago