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babunello [35]
2 years ago
12

9 Ms. Levin wrote the algebraic expression on the board 25(w +9) Select the statement that describes the algebraic expression Ma

rk all that apply A. 25, w, and 9 are three factors B. It has two terms C. It represents 9 added to the product of 15 and w D. One of the terms is (w + 9) E. It represents the sum of a product F. It represents a number times a sum​
Mathematics
1 answer:
kiruha [24]2 years ago
3 0

Answer:

the answer is 2

Step-by-step explanation:

you just do Pemdas and with the variable.

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Find the unit price for each option shown below. Round to the nearest cent when necessary. Option I: 10 candy bars for $6.75 Opt
natita [175]
Option I: 10 candy bars for $6.75 

<span>6.75/10 = 0.68 </span>

<span>Option II: 12 candy bars for $7.25 </span>

<span>7.25 / 12 = 0.60 </span>


6 0
3 years ago
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Given the differential Equation y'+2y=2e^x ;solve this equation using the integration factor; solve for y to get the general sol
SCORPION-xisa [38]

y'+2y=2e^x\Longrightarrow y'=2e^x-2y

If f'(x)=g(x) then y=\int{g(x)dx}

So we extract,

y=\int{2e^x-2x}dx

Which becomes,

y=2e^x-x^2+C

Hope this helps.

r3t40

5 0
3 years ago
Brooke found the equation of the line passing through the points (–7, 25) and (–4, 13) in slope-intercept form as follows. Step
Katen [24]

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Step-by- explanation:

Hope this helps :)

8 0
3 years ago
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Suppose the weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams. The weights
user100 [1]

Answer:

a) 0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b) The weight that 80% of the apples exceed is of 78.28g.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Weights of apples are normally distributed with a mean of 85 grams and a standard deviation of 8 grams.

This means that \mu = 85, \sigma = 8

a. Find the probability a randomly chosen apple exceeds 100 g in weight.

This is 1 subtracted by the p-value of Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 85}{8}

Z = 1.875

Z = 1.875 has a p-value of 0.9697

1 - 0.9696 = 0.0304

0.0304 = 3.04% probability a randomly chosen apple exceeds 100 g in weight.

b. What weight do 80% of the apples exceed?

This is the 100 - 80 = 20th percentile, which is X when Z has a p-value of 0.2, so X when Z = -0.84.

Z = \frac{X - \mu}{\sigma}

-0.84 = \frac{X- 85}{8}

X - 85 = -0.84*8

X = 78.28

The weight that 80% of the apples exceed is of 78.28g.

5 0
2 years ago
What would be the third step in simplifying the expression 4 2 ÷ (2 · 9) + 5?
ludmilkaskok [199]
P
E
M
D
A
S

okay since the first step is parenthesis, the next step would be exponents but you have none so you skip to multiplication, then you divide

divide is your answer
8 0
3 years ago
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