If one is 5"x3", and the other having the same orientation is 3"x?, then
by similar figures,
5/3=3/x
cross multiply,
5x=3*3
x=9/5=1.8"
With the original figure, it is possible to validate the above answer.
Answer:
W=7 and L=11
Step-by-step explanation:
We have two unknowns so we must create two equations.
First the problem states that length of a rectangle is 10 yd less than three times the width so: L= 3w-10
Next we are given the area so: L X W = 77
Then solve for the variable algebraically. It is just a system of equations.
3W^2 - 10W - 77 = 0
(3W + 11)(W - 7) = 0
W = -11/3 and/or W=7
Discard the negative solution as the width of the rectangle cannot be less then 0.
So W=7
Plug that into the first equation.
3(7)-10= 11 so L=11
Answer:
There is not enough information
Step-by-step explanation:
Answer:
16=53
Step-by-step explanation:
12.9 x 14 .9 + 6= 12
Answer:
915 in²
Step-by-step explanation:
The area of the rectangle :
Length = 32 inches
Width = 25 - (10+10) = 25 - 20 = 5 inches
Area of rectangle = Length * width
Area = 32 * 5 = 160 in²
Area of triangle :
Base = 25 inches
Height = (46 - 32) inches = 14 inches
Area of triangle = 1/2 * base * height
Area of triangle = 1/2 * 25 * 14 = 175 in²
Total area = (160 + 175)in² = 335 in²
Total area of cardboard :
50 inches * 25 inches = 1250 in²
Amount of cardboard not used :
(1250 - 335) in² = 915 in²