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Nady [450]
3 years ago
11

Write the expression as the sine or cosine of an angle sin(pi/7) cos(x) + cos(pi/7) sin(x)

Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
5 0

Answer:

\sin(\frac{\pi}{7}+x)

Step-by-step explanation:

We are going to use the identity

\sin(a+b)=\sin(a)\cos(b)+\cos(a)\sin(b)

because this identities right hand side matches your expression where

a=\frac{\pi}{7} and b=x.

So we have that \sin(\frac{\pi}{7})\cos(x)+\cos(\frac{\pi}{7})\sin(x) is equal to \sin(\frac{\pi}{7}+x).

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Step-by-step explanation:

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Answer:

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12345 [234]
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6 0
3 years ago
Someone please help me with this math problem! :(
Assoli18 [71]
Area of a parallelogram=base x heigth
Data:
base=(2x+3)
heigth=(ax+5)
area of this parallelogram=8x²+bx+15

Therefore:
8x²+bx+15=(2x+3)(ax+5)
8x²+bx+15=2ax²+10x+3ax+15
8x²+bx+15=2ax²+(10+3a)x+15

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