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bezimeni [28]
2 years ago
9

Multiply the following expressions 81x5y6 × (-1x2y)​

Mathematics
1 answer:
Gnom [1K]2 years ago
5 0
Answer: -4860y^2

Solution:
81 x (5y x 6) x (-2y)
-81 x 5y x 6 x 2y
= -4860y^2
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The product of a binomial and a trinomial is x3+3x2-x+2x2+6x-2 Which expression is equivalent to this
solong [7]
The answer is the first one.
Explanation:
X^3 stays the same because there are no other cubed numbers in the problem
Next you combine the x^2s
The x^2s are +3x^2 and +2x^2
Since they are both positive, you add them: 3x^2 + 2x^2 = 5x^2
Next you do the x values
-x and +6x, also known as 6x - x = 5x
Lastly, you just add in the -2 and get:
X^3 + 5x^2 + 5x - 2
8 0
3 years ago
If a building is 2,716 feet tall, how tall is it in miles if 1 mile is 5,280 feet
avanturin [10]

(2,716 feet) x (1mile / 5,280 feet)  =  <em>0.5144 mile</em>  (rounded)


7 0
4 years ago
Read 2 more answers
FIRST TO ANSWER GETS BRAINLIEST: The average age of one hundred Year 9 students is 14 y 10 m. The average age of one hundred Yea
Dvinal [7]

Answer:

2) 14 y 2 m

Step-by-step explanation:

Year 9 students: total age= 100* 14 10/12= 1400 +100*5/6= 1483 y 8 m

Year 8 students: total age= 100* 13 6/12= 1350 y

Total age of 200 students: 1483 y 8 m + 1350 y= 2833 y 8 m

Average age= 2833  8/12  ÷ 200= (12*2833+8)/12 ÷ 200 = 34004/(12*200)= 34004/2400= 14  404/2400 ≈ 14 1/6 y= 14 y 2 m

4 0
3 years ago
Divide and draw a quick picture
weqwewe [10]
What picture ? Did you attached it
5 0
3 years ago
Kwan hiked up a hill at 4 km/h and back down at 6 km/h. His total hiking time was 3 hours. How long did the trip up the hill tak
Leya [2.2K]

Let the time to hike up the hill  = t

As given that the total time time up and down is 3 hrs,  therefore

The time down the hill = 3-t

The distance up and down is the same.

Distance = speed * time

4t=6(3-t)

4t=18-6t

10t=18

t=1.8

Hence, time taken to uphill = 1.8 hours

Time taken to down hill = 3-18 = 1.2 hours

3 0
3 years ago
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