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slava [35]
3 years ago
15

Which function has an inverse that is also a function?

Mathematics
2 answers:
aliya0001 [1]3 years ago
8 0

Answer:

C){(-1, 3), (0, 4), (1, 14), (5, 6), (7, 2)}

Step-by-step explanation:

The one-to-one function has inverse where the inverse is also function.

That is, there should be unique output for each input values.

Look at the options, Option C) only has unique output for each input values.

Therefore, the answer C){(-1, 3), (0, 4), (1, 14), (5, 6), (7, 2)}

Hope this will helpful.

Thank you.

Rama09 [41]3 years ago
3 0
The function that has an inverse that is also a function will have no repeated y-values. The appropriate choice is the third one.
  {(-1, 3), (0, 4), (1, 14), (5, 6), (7, 2)}
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In training for a swim meet, Logan swam 750 meters in \large \frac {1}{3}
worty [1.4K]

Answer:

500

Step-by-step explanation:

7 0
4 years ago
Use a transformation to solve the equation. f – 12 = –35 A. f = –47 B. f = –23 C. f = 23 D. f = 47
andrew-mc [135]
F – 12 = –35

Here, we must solve for f

f - 12 = -35
   +12    +12

f = -35 + 12
f = -23

Answer: f = -23
5 0
3 years ago
PLS HELP ME
IgorLugansk [536]

Answer :

Option B

Step by step explanation :

As we can see in figure, Triangle is right angled at A

In ∆ABC

By Pythagoras theorem,

BC² = AC² + AB²

=> BC² = (3)² + (4)²

=> BC² = 9 + 16

=> BC² = 25

=> BC = 5 cm

We know,

\:\mathsf{Area \:of\: triangle}=\:\mathsf{\frac{1}{2}\: x\: base\: x\: height}

Here,

base = AC = 3cm

height = AB = 4cm

=> \:\mathsf{Area \:of\: triangle}=\:\mathsf{\frac{1}{2} \:x\: 3cm\: x\:4cm}

=> \:\mathsf{Area \:of\: triangle\: = \:3cm\: x\: 2cm}

=> \:\bf\boxed{Area \:of\: triangle\: = \:6cm²}

As BC = DE

And then BD = EC

it shows the property of rectangle

So BD = 6 cm

Now,

\:\mathsf{Area \:of\: rectangle\: =\: length \:x\: width}

=> Area of rectangle = 6cm x 5cm

=> \:\bf\boxed{Area\: of\: rectangle\: = \:30cm²}

Now,

Area of the figure = Area of rectangle + Area of triangle

=> Area of the figure = 30cm² + 6cm²

=> \:\bf\boxed{Area\: of\: the\: figure\: = \:36cm²}

Therefore, <u>option B</u> is the correct answer for this question.

3 0
3 years ago
Given: f(x) = x - 7 and h(x) = 2x + 3<br><br> Write the rule for h(f(x)).
OLga [1]
So basically you just want to replace all the x's in the h(x) equation with the f(x) equation. 

h(x-7) = 2(x-7) + 3 
h(x) = 2x -14 + 3 
h(x) = 2x - 11 
5 0
4 years ago
Read 2 more answers
The diagonals of a parallelogram ABCD intersect at O.find ar(AOB),if ar(ABCD)is 44cm^2
prisoha [69]

Answer:

11\text{ cm}^2

Step-by-step explanation:

Given: In a parallelogram ABCD, diagonals intersect at O and ar(ABCD) is 44 \text{cm}^2.

We need to find the area of triangle AOB.

We know that each diagonal divide the parallelogram in two equal parts and diagonals bisect each other.

It means both diagonals divide the parallelogram in 4 equal parts.

ar(AOB)=\dfrac{1}{4}\times ar(ABCD)

ar(AOB)=\dfrac{1}{4}\times 44

ar(AOB)=11

Hence, the values of ar(AOB) is 11\text{ cm}^2.

5 0
3 years ago
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