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2 years ago

Y=5x-9 y=5x+9 solve with substitution

Mathematics

1 answer:

Lesechka [4]2 years ago

8 0

Answer:

No solution

Step-by-step explanation:

y=5x-9

y=5x+9

5x + 9 = 5x - 9

- 9 - 9

5x = 5x - 18

- 5x - 5x

0 = 18

No solution

Hope this helps!

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For the following telescoping series, find a formula for the nth term of the sequence of partial sums {Sn}. Then evaluate limn→[

Ivenika [448]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

Given value:

$1) \sum ^{\infty}_{k = 1} \frac{1}{k+1} - \frac{1}{k+2}\\\\2) \sum ^{\infty}_{k = 1} \frac{1}{(k+6)(k+7)}$

Solve point 1 that is $\sum ^{\infty}_{k = 1} \frac{1}{k+1} - \frac{1}{k+2}\\\\$ :

when,

$k= 1 \to s_1 = \frac{1}{1+1} - \frac{1}{1+2}\\\\$

$= \frac{1}{2} - \frac{1}{3}\\\\$

$k= 2 \to s_2 = \frac{1}{2+1} - \frac{1}{2+2}\\\\$

$= \frac{1}{3} - \frac{1}{4}\\\\$

$k= 3 \to s_3 = \frac{1}{3+1} - \frac{1}{3+2}\\\\$

$= \frac{1}{4} - \frac{1}{5}\\\\$

$k= n^ \to s_n = \frac{1}{n+1} - \frac{1}{n+2}\\\\$

Calculate the sum $(S=s_1+s_2+s_3+......+s_n)$

$S=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+.....\frac{1}{n+1}-\frac{1}{n+2}\\\\$

$=\frac{1}{2}-\frac{1}{5}+\frac{1}{n+1}-\frac{1}{n+2}\\\\$

When $s_n \ \ dt_{n \to 0}$

$=\frac{1}{2}-\frac{1}{5}+\frac{1}{0+1}-\frac{1}{0+2}\\\\=\frac{1}{2}-\frac{1}{5}+\frac{1}{1}-\frac{1}{2}\\\\= 1 -\frac{1}{5}\\\\= \frac{5-1}{5}\\\\= \frac{4}{5}\\\\$

$\boxed{\text{In point 1:} \sum ^{\infty}_{k = 1} \frac{1}{k+1} - \frac{1}{k+2} =\frac{4}{5}}$

In point 2: $\sum ^{\infty}_{k = 1} \frac{1}{(k+6)(k+7)}$

when,

$k= 1 \to s_1 = \frac{1}{(1+6)(1+7)}\\\\$

$= \frac{1}{7 \times 8}\\\\= \frac{1}{56}$

$k= 2 \to s_1 = \frac{1}{(2+6)(2+7)}\\\\$

$= \frac{1}{8 \times 9}\\\\= \frac{1}{72}$

$k= 3 \to s_1 = \frac{1}{(3+6)(3+7)}\\\\$

$= \frac{1}{9 \times 10} \\\\ = \frac{1}{90}\\\\$

$k= n^ \to s_n = \frac{1}{(n+6)(n+7)}\\\\$

calculate the sum: $S= s_1+s_2+s_3+s_n\\$

$S= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}....+\frac{1}{(n+6)(n+7)}\\\\$

when $s_n \ \ dt_{n \to 0}$

$S= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}....+\frac{1}{(0+6)(0+7)}\\\\= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}....+\frac{1}{6 \times 7}\\\\= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}+\frac{1}{42}\\\\=\frac{45+35+28+60}{2520}\\\\=\frac{168}{2520}\\\\=0.066$

$\boxed{\text{In point 2:} \sum ^{\infty}_{k = 1} \frac{1}{(n+6)(n+7)} = 0.066}$

8 0

3 years ago

Solving Systems of Linear Equations by graphing. 3y+4x=3 and x+3y=-6. Can someone help me with where the lines intersect and sho

Greeley [361]

The best way to do this question is to use elimination. Elimination is a way to find out the POINT OF INTERSECTION between two lines. Let me show you how.

3y+4x=3
x+3y=-6

Elimination is a way to remove any same variable with the same coefficient. In this case, there is 3y in both equations. In this case, we subtract to eliminate.

3y-3y+4x-x=3+6 It's plus 6 because two negatives become positive.
3x=9 Divide both sides by 3
x=3

Now you can find y.

x+3y=-6
3+3y=-6
3y=-9
y=-3

Therefore, the POI is (3,-3). I hope you understand this. Make sure to mark as brainliest.

8 0

3 years ago

Which quadrant is the point (-3,5) located?

nlexa [21]

Quadrant ll
Hope this helps

8 0

3 years ago

Read 2 more answers

Solve for X with steps

yarga [219]

Answer:

x= 17.78

Step-by-step explanation:

a^2 + b^2 = c^2

8^2 + b^2 = 18^2

b^2= 18^2-8^2

b^2 = 260

so you have to take square root i can't show the symbol of it so i am just do it

b= 16.12

then you use that for other tringle

same formula

24^2= x^2+16.12^2

x^2= 316.15

x= 17.78

6 0

3 years ago

Least to greatest √5,-2.1,0.5,-0.5,5/100

Sladkaya [172]

Answer: -2.1, -0.5, 5/100, 0.5, √5

Step-by-step explanation:

Start with the negative numbers. Take the absolute value - the ones with the largest absolute value are the farthest from 0, so they are the smallest numbers.

-2.1, -0.5

Then, convert the numbers not in decimals to decimals.

5/100 = 0.05

√5 is about 2.3.

5/100, 0.5, √5

6 0

4 years ago