14+5(x+3)-7
14+(5x+15)-7
7+5x+15
5x+22
The two angles (6x+4) and 32 degrees are complementary angles. They add to 90 degrees. The two angles are adjacent and form a right angle. The right angle marker is the square marker. Two adjacent right angles form a straight angle (180 degrees)
Add up the angles and set the sum equal to 90. Then solve for x
(6x+4) + (32) = 90
6x+4 + 32 = 90
6x+36 = 90
6x+36-36 = 90-36 .... subtract 36 from both sides
6x = 54
6x/6 = 54/6 ... divide both sides by 6
x = 9
Since x = 9, this means that
6x+4 = 6*9+4 = 54+4 = 58
So the missing angle is 58 degrees (note how 58+32 = 90)
Y^3=x and 3y=x^2 is nonlinear
the others are linear
Answer: The slope of two parallel lines are same. Since one pair of opposite sides are equal and parallel, therefore the another set of opposite sides is also parallel and equal. The opposite sides are prallel and equation, so the quadrilateral PQRS is a parallelogram.
