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2 years ago

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At a big cat reserve, a male Bengal tiger weighs more than a female Bengal tiger. The male tiger weighs 445 pounds. The differen

ce in the weights of the tigers is 97 pounds. The zookeeper created the bar diagram and equation below to find the difference in their weights. A bar diagram. The top bar contains 445. The bottom bars contain f and 97. 445 = f 97 What is the value of f ? 348 pounds 358 pounds 532 pounds 542 pounds.

2 answers:

iragen [17]2 years ago

8 0

Answer:

348

Step-by-step explanation:

if the male weighs 445 and the difference in the weight is 97 you know to subtract the 97 since it syas the male weighs more.

kolbaska11 [484]2 years ago

4 0

The value of f is 348 pounds.

Given

At a big cat reserve, a male Bengal tiger weighs more than a female Bengal tiger.

The male tiger weighs 445 pounds.

The difference in the weight of the tigers is 97 pounds.

<h3>Difference;</h3>

The meaning of DIFFERENCE is the quality or state of being dissimilar or different.

The zookeeper created the bar diagram and the equation below is given as:

$\rm 445=f+97$

On solving the equation the value of f is;

$\rm 445=f+97\\\\f = 445-97\\\\f= 348$

Hence, the value of f is 348 pounds.

To know more about the differences click the link given below.

brainly.com/question/11572024

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In ΔABC, ∠B measures 35° and the values of a and b are 19 and 11, respectively. Find the remaining measurements of the triangle,

Anna35 [415]

Answer:

a) ∠A = 82.2° , ∠C = 62.8° , c = 17.01

Step-by-step explanation:

<u><em>Explanation</em></u>:-

<u><em>Step(i)</em></u>:-

Given data ∠B measures 35° and the values of a and b are 19 and 11

∠B = 35° and sides a = 19 and b = 11

<em>By using sine rule </em>

<em></em> $\frac{a}{sin A} = \frac{b}{sin B} = \frac{c}{Sin C} = 2 R$ <em></em>

now we will use

$\frac{a}{sin A} = \frac{b}{sin B}$

$\frac{19}{sin A} = \frac{11}{sin 35}$

cross multiplication , we get

$\frac{19 X sin 35}{11} = sinA$

<em>sin A = 0.990</em>

<em>A = sin⁻¹( 0.990) = 82.2°</em>

<em> ∠A = 82.2°</em>

<u><em>Step(ii):-</em></u>

we know that ∠A +∠B +∠C = 180°

∠C = 180° - ∠A -∠B

∠C = 180° -82.2°-35°

∠C = 62.8°

<u><em>Step(iii)</em></u>:-

<em>we will use formula</em>

<em></em> $\frac{b}{sin B} = \frac{c}{Sin C}$ <em></em>

<em></em> $\frac{11}{sin 35} = \frac{c}{Sin 62.8}$ <em></em>

$\frac{11 X sin (62.8)}{sin 35} = C$

<em>c = 17.01</em>

<u><em>Final answer</em></u>:-

<em> ∠A = 82.2° , ∠C = 62.8° , c = 17.01</em>

4 0

3 years ago

Y=2x-2 and 4x+2y=12. solve the equation PLEASE SHOW WORK

diamong [38]

<h3>The solution as an ordered pair is (x,y) = (2,2)</h3><h3>x = 2 and y = 2 pair up together.</h3>

===============================

Work Shown:

4x+2y = 12

4x+2( y ) = 12

4x+2( 2x-2 ) = 12 ... replace y with 2x-2

4x+2( 2x ) + 2( -2 ) = 12 ... distribution rule

4x+4x-4 = 12

8x-4 = 12

8x-4+4 = 12+4 ... add 4 to both sides

8x = 16

8x/8 = 16/8 ... divide both sides by 8

x = 2 is the first part of the answer

Use x = 2 to find y

y = 2x-2

y = 2(2)-2 ... replace x with 2

y = 4-2

y = 2 is the second part of the answer

8 0

3 years ago

Read 2 more answers

Can someone help me please

Misha Larkins [42]

Answer:

x= 13, angle 1= 37, and angle 2= 53

Step-by-step explanation:

So you have 2x+11+1+4x=90 degrees

If you simplify it, it becomes 6x+12=90 degrees

Then, you rearrange; 6x=90-12 or 6x= 78

So then, x=13

For angle 1 its 2x+11= 37 degrees

And angle 2 is 1+4x= 53 degrees

7 0

3 years ago

Please help me im really bad only higher grades can answer

myrzilka [38]

Positive sorry if it’s wrong good luck

3 0

3 years ago

Read 2 more answers

Find x in the following diagram

andreyandreev [35.5K]

Answer:

x = 71

Step-by-step explanation:

The sum of the measures of the exterior angles of a polygon is always 360°.

A triangle has 3 exterior angles.

152+ 137+x = 360

Combine like terms

289 +x = 360

Subtract 289 from each side

289-289+x=360-289

x = 71

8 0

3 years ago