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4vir4ik [10]
3 years ago
8

If a function uses variables other than x and y for its input and output variables, you take the original equation and solve for

the input variable to find the inverse.
TRUE
OR
FALSE
?
Mathematics
2 answers:
grandymaker [24]3 years ago
5 0
For the answer to the question, i<span>f a function uses variables other than x and y for its input and output variables, you take the original equation and solve for the input variable to find the inverse.

The answer is Simply true. But in real life it's false.

I hope my answer helped you.</span>
Usimov [2.4K]3 years ago
4 0

Answer:

<h2>False.</h2>

Step-by-step explanation:

When we talk about the input variable, it refers to the independent variable which most of the time is expressed as <em>x</em>. That means the output variable often refers to <em>y</em>, because that's the image or range.

So, in this case, if we want to find the inverse of a function, we just have to solve for <em>x, </em>that is, for the input variable. For example, if we have the following function

h=2t

The input variable would be t, so the inverse would be found by solving for that variable

t=\frac{h}{2}

<em>However, we need to switch the position of variables to find the inverse function as follows</em>

h=\frac{t}{2}

Therefore, to the inverse of a function we certainly have to solve for the input variable, but then we need to do an extra step, swtich variable's position, that's why this statement is false, because it doesn't express the full process.

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Step-by-step explanation:

Step 1. Ok, so we need to see how many times 9 will divide into 18.

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3 years ago
The Wind Mountain excavation site in New Mexico is an important archaeological location of the ancient Native American Anasazi c
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Answer:

a) 28

b)

Class Limits  Class Boundaries   Midpoint    f      Rf         Cf

10 - 37            9.5-37.5                   23.5            7     0.096     7      

38 - 65           37.5-65.5                 51.5           25    0.342     32    

66 - 93           65.5-93.5                 79.5          26    0.356     58    

94 -  121        93.5-121.5                   107.5         9     0.123       67    

122 - 149      121.5-149.5                  135.5         5      0.068     72  

150 - 177       149.5-177.5                  163.5        0         0.0      72    

178 - 205       177.5-20.5                  191.5         1       0.014      73  

Total                                                                  73          1.0    

c)

The histogram is in attached file.

Step-by-step explanation:

a)

The width of class interval=range/desired number of classes

The width of class interval=(maximum-minimum)/7

The width of class interval=(200-10)/7

The width of class interval=190/7

The width of class interval=27.14=28 (rounded to next whole number)

Part(b) and part (c) is explained in attached word document.

Download docx
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