This is a right angle triangle and you use the Pythagorean theorem to solve for the hypotenuse (the diagonal)
A^2 + B^2 = C^2
8^2 + 8^2 = C^2
64 + 64 = C^2
128 = C^2
C = square_root (128)
C = 11 (to the nearest whole number)
The diagonal is 11 feet (to the nearest whole number)
Answer:
82
Step-by-step explanation:
Let's first figure out what the first number is and use that to solve for the next. The problem states that the numbers are consecutive. So the 2nd number word be 1 plus the first.
The sum of 4 consecutive numbers:
1st = x
2nd = x + 1
3rd = x + 2
4th = x + 3
The sum of 4 consecutive number is 326.
1st + 2nd + 3rd + 4th = 326
x + (x + 1) + (x + 2) + (x + 3) = 326
Combine like terms:
4x + 6 = 326
Then we subtract 6 from both sides to isolate 4x:
4x + 6 - 6 = 326 - 6
4x = 320
Then we divide both sides by 4 to isolate x:
4x/4 = 320/4
x = 80
So the first number is 79
Now to get the second, let's just add 1.
80 + 1 = 81
Let's check if our answer would be correct:
80 + 81 + 82 + 83
= 326
Answer:
The answer would be the large album has 54 more stamps than the small album.
Step-by-step explanation:
... 92 - 38 = 54
Do you need a drawing done though?
Answer: OPTION D.
Step-by-step explanation:
The symbol of the inequality ">" means "greater than". Then, -5 is greater than -6.
If a negative number -a is greater than other negative number -b , then the distance between -a and zero is shorter than the distance between -b and zero.
You can see in the number line attached that -5 is closer to 0 than -6. Therefore, -5 is located to the right of -6.
Answer:
Step-by-step explanation:
Let number of pounds of cans collected by Amy = 
Let number of pounds of cans collected by Bruce = 
Let number of pounds of cans collected by Carlos = 
As per question statement, total number of cans collected = 168
..... (1)
Number of pounds collected by Bruce is 
rd of the pounds of cans collected by Carlos.
Number of pounds collected by Amy is equal to number of pounds collected by Bruce and Carlos combined.
Using equation (2):
Using equations (2) and (3) in equation (1), we get:
Using equation (2):
