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Maru [420]
4 years ago
14

A student council sold 856 copies of a school yearbook, four fifths of the students at the school bought a copy , how many stude

nts did not buy a yearbook
Mathematics
1 answer:
kumpel [21]4 years ago
8 0

Answer:

I am guessing about 150 - 200 students did not buy a yearbook.

Step-by-step explanation:

First let's assume that there are 1,000 or so students in the school. 856 would be a little over 4/5 of 1,000 just as 8 would be 4/5 of 10.

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The path of a race will be drawn on a coordinate grid like the one shown below. The starting point of the race will be at (−5.3,
m_a_m_a [10]

The Cartesian coordinate plane, specify locations by a pair of coordinates that indicate the magnitude in perpendicular, x, and y directions

The correct responses are;

  • Part A: The starting point is in the second quadrant and the finishing point is in the fourth quadrant.
  • Part B: The starting point and the check point are on different quadrant. Both points are on the same horizontal line.

Reasons:

The location of the start point of the race = (-5.3, 1)

Location of the finishing point = (1, -5.3)

Part A: The signs of the <em>x</em> and <em>y</em>-values in the quadrants are;

  • \begin{tabular}{|cc|c|}Quad II, x -ve, y +ve&&Quad I, x, and y are +ve\\&&\\Quad III, x -ve, y -ve&&Quad IV, x +ve, y -ve\end{array}\right]

The coordinates of the starting point is (-5.3, 1), therefore, given that the x-

coordinate is negative and the y-coordinate is positive, the quadrant of the

starting point is quadrant II (the second quadrant).

  • <u>The quadrant of the starting point is the second quadrant</u>.

The coordinates of the finishing point is (1, -5.3), the x-value is positive and

the y-value is negative, which indicates that the quadrant of the finishing

point is quadrant IV (the fourth quadrant).

  • <u>The quadrant of the finishing point is the fourth quadrant</u>.

Part B: The location of the checkpoint is; (5.3, 1)

The difference is that the x-value of the checkpoint is positive while the x-value of the starting point is negative, and they are therefore on different quadrants.

The similarity is that, the magnitude of the <em>x</em>, and <em>y</em> values of the coordinates of the check point and the starting point are the same. Therefore, the checkpoint and the starting point are on <u>the same horizontal line</u>.

Learn more about the Cartesian coordinate plane here:

brainly.com/question/17877300

brainly.com/question/16177011

8 0
3 years ago
(4u^3+6u^2+7)+(6u^3-2u+7)<br> Simplify the sum'
Pie

Hi Nova


(4u³+6u²+7)+(6u³-2u+7)

= 4u³+6u²+7+6u³-2u+7

Combine like terms

( 4u³+6u³)+(6u²)+(-2u)+(7+7)

= 10u³+6u² -2u+14

There no like terms so you can not simplify the sum


I hope that's help and if you have questions please ask !

3 0
4 years ago
Did i do this correclty
Paraphin [41]

Answer:

Yes you did!

Step-by-step explanation:

Sweet job!

7 0
3 years ago
Read 2 more answers
How can a triangular prism have a greater volume than a rectangular prism?
nevsk [136]

Answer:

If the triangular prism is bigger than the rectangular prism, it will have a greater volume. There are also many other reasons listed below:

Possible reasons:

  • If the triangular prism is bigger than the rectangular prism, it will have a greater volume
  • The rectangular prism could have less width than the triangular prism
  • The rectangular prism could have less depth than the triangular prism
  • The rectangular prism could have less length than the triangular prism

<em>Please mark Brainliest if correct.</em>

<em>Sorry if it is not correct.</em>

4 0
3 years ago
Read 2 more answers
Use the properties of 30-60-90 and 45-45-90 triangles to solve for x in each of the problems below. Then decode the secret messa
Flauer [41]

With the help of trigonometric function, the above problems have been calculated. See explanation below.

<h3>What are Trigonometric functions?</h3>

The term "trigonometric function" refers to functions that are periodic in nature and that shed light on how a right-angled triangle's angles and sides relate to one another.

The solutions to x in the respective problems is given as follows:

1) x = 5 /Sin(30°)

x = 10

!) Sin(45°) = 4/x

x = 4/sin(45°)

x = 4√2

I) Cos(45°) = √3 / x

x = √3 / Cos(45°)

x = √6

E) Tan(60°)

= (3√3) / x

x = (3√3) / 3

W) In trigonometry, every right-triangle that is isosceles in nature, the angle made by the legs and the hypotenuse will always equal 45°.

x = 45°

N) x² + x² = (7√2)²

x = 7

V) Tan(60°) = 7 / x

x = 7√3/3

K) x² + x² = (9)²

x = 9/√2

Y) Sin(60°) = 7√3/x

x = 14

M) Sin(30°) = x/11

x = 11/2

T) Sin(45°) = x/√10

x = √5

A) x + 2x + 90° = 180°

x = 30°

O) Sin(45°) = √2 / x

x = 2

R) Tan(30°) = x / 4

x = 4/√3

= 4√3 / 3

S) Sin(60°) = x / (10/3)

x = (5√3) / 3

Learn more about Trigonometric functions at:

brainly.com/question/14421002

#SPJ1

3 0
2 years ago
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