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Maru [420]
3 years ago
14

A student council sold 856 copies of a school yearbook, four fifths of the students at the school bought a copy , how many stude

nts did not buy a yearbook
Mathematics
1 answer:
kumpel [21]3 years ago
8 0

Answer:

I am guessing about 150 - 200 students did not buy a yearbook.

Step-by-step explanation:

First let's assume that there are 1,000 or so students in the school. 856 would be a little over 4/5 of 1,000 just as 8 would be 4/5 of 10.

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Solve the inequality for x. Show each step of the solution.10x > 2(8x – 3) – 18
Luden [163]

Answer: x<4

Given the inequality:

10x>2(8x-3)-18

We want to solve the inequality for x.

First, distribute the bracket on the right side of the inequality.

\begin{gathered} 10x>2(8x)-2(3)-18 \\ 10x>16x-6-18 \\ 10x>16x-24 \end{gathered}

Next, subtract 10x from both sides of the inequality.

\begin{gathered} 10x-10x>16x-10x-24 \\ 0>6x-24 \end{gathered}

Add 24 to both sides of the inequality.

\begin{gathered} 0+24>6x-24+24 \\ 24>6x \end{gathered}

Divide both sides of the inequality by 6.

\begin{gathered} \frac{24}{6}>\frac{6x}{6} \\ 4>x \\ \implies x

The solution to the inequality is x<4.

6 0
1 year ago
Three circular arcs of radius units bound the region shown. Arcs and are quarter-circles, and arc is a semicircle. What is the a
mestny [16]

Answer:

Three circular arcs of radius $5$ units bound the region shown. Arcs $AB$ and $AD$ are quarter-circles, and arc $BCD$ is a semicircle.

Step-by-step explanation:

8 0
2 years ago
Factor completely:<br>64 - y^3
madam [21]
From your equation, you can see that you have a difference of two cubes (aka two cubes being subtracted): 64, which is 4^{3}, and y^{3}.

There is rule for the difference of two cubes:
The difference of two cubes is equal to the difference of the cube roots times a binomial, which is the sum of the squares of the roots plus the product of the roots.

That sounds pretty confusing, but it's much easier to understand when put mathematically. Let's say our two cubes are a^{3} and b^{3}. The difference of those two cubes is:
a^{3} - b^{3} = (a - b)( a^{2} + ab + b^{2})

In our problem, a = 4 (since a^{3} = 64) and b = y (since b^{3} = y^{3}. Plug these values into the rule to find the factor of 64 - y^3:
64 - y^3 \\&#10;= (4 - y)( 4^{2} + 4y + y^{2}) \\&#10;=  (4 - y)( 16 + 4y + y^{2})

-----

Answer: (4 - y)( 16 + 4y + y^{2})

8 0
3 years ago
Can someone be my friend
marta [7]

Answer: yes

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Suppose a set of data about the spread (in hundreds of acres) of a food-borne bacteria (after t weeks) in lettuce has the follow
Alexxandr [17]

Answer:

A sinusoidal model would be used

The kind of function that have consistency in the periodic rate of change is the Average rate of changes

Step-by-step explanation:

The type of model that would be used is sinusoidal model and this is because there is periodic change in the values given ( i.e the rate of changes given )

For percentage rate of changes :

starting from 0.9% there is an increase to 1.3% then a decrease to 1.1% and a further decrease to 1% before an increase to 1.3% and another decrease to 1%

For Average rate of changes:

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This relation ( sinusoidal model ) is best suited for a linear model because there is a periodic rate of change in the functions

The kind of function that have consistency in the period rate of change is the Average rate of changes

6 0
3 years ago
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