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Fittoniya [83]
3 years ago
6

Find the value of xx and yy in the parallelogram below.

Mathematics
2 answers:
VikaD [51]3 years ago
6 0

Answer: x = 7 and y = -17

Step-by-step explanation:

Opposite sides of parallelograms are equal.

-5y + 3 = 88

-5y = 85

y = -17

10x - 7 = 63

10x = 70

x = 7

agasfer [191]3 years ago
5 0

Mark the definition of parallelogram

  • Opposite sides are parallel
  • Opposite sides are equal

So

  • 10x-7=63
  • 10x=70
  • x=7

And

  • -5y+3=83
  • -5y=80
  • y=-16
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4/3x + 1/6x = 36 (solve for x please help I have no idea what it is!!!!!!!
ElenaW [278]

Answer:

x = 24

Step-by-step explanation:

\frac{4}{3}x + \frac{1}{6}x = 36

Make the denominator the same by multiplying the first fraction by 2 to make both denominators 6.

\frac{8}{6}x + \frac{1}{6}x = 36

Now we can calculate the numerators and keep the denominators the same.

\frac{9}{6}x = 36

Find x.

\frac{6}{6}x = \frac{6}{9} × 36

x = 24

7 0
3 years ago
Best and correct answer gets brainliest!!!
dmitriy555 [2]
59 degrees!
because you set up your problem: 3c+2+2c-7=90
then combine all like terms: 5c-5=90
Add 5 to both sides: 5c=95
then divide both sides by 5: c=19
Plug in your answer: 3(19)+2=59
8 0
3 years ago
If 2x^2+2x-8 is the quotient when x+3 divides P(x), which of th3 following is the quotient when 2x+6 divides p(x)?
maria [59]

Answer: A

2x^2+2x-8 is the quotient when x+3 divides P(x)

=> P(x) = (2x² + 2x -8)(x + 3) = 2(x² + x - 4)(x + 3) = (x² + x - 4) (2x + 6)

=> the quotient when 2x+6 divides p(x) is x² + x - 4

Step-by-step explanation:

7 0
3 years ago
College Math!!! I did the first half of the question, I just need the bottom half of it.
ella [17]

Answer:

-49

Step-by-step explanation:

\int _{-5}^{-2}\:\left(8\:w\left(r\right)-3\right)dr = \int _{-5}^{-2}\:8\:w\left(r\right)dr -3 (-2 -(-5)) = 8 \int _{-5}^{-2}\:\:w\left(r\right)dr -9 =8(-5) -9 = -49

7 0
3 years ago
Find an equation of the tangent to the curve at the given point by both eliminating the parameter and without eliminating the pa
Misha Larkins [42]

Answer:

y = 2x − 1

Step-by-step explanation:

By eliminating the parameter, first solve for t:

x = 4 + ln(t)

x − 4 = ln(t)

e^(x − 4) = t

Substitute:

y = t² + 6

y = (e^(x − 4))² + 6

y = e^(2x − 8) + 6

Taking derivative using chain rule:

dy/dx = e^(2x − 8) (2)

dy/dx = 2 e^(2x − 8)

Evaluating at x = 4:

dy/dx = 2 e^(8 − 8)

dy/dx = 2

Writing equation of line using point-slope form:

y − 7 = 2 (x − 4)

y = 2x − 1

Now, without eliminating the parameter, take derivative with respect to t:

x = 4 + ln(t)

dx/dt = 1/t

y = t² + 6

dy/dt = 2t

Finding dy/dx:

dy/dx = (dy/dt) / (dx/dt)

dy/dx = (2t) / (1/t)

dy/dx = 2t²

At the point (4, 7), t = 1.  Evaluating the derivative:

dy/dx = 2(1)²

dy/dx = 2

Writing equation of line using point-slope form:

y − 7 = 2 (x − 4)

y = 2x − 1

6 0
3 years ago
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