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2 years ago

Help me solve this problem: -3(x^-2 y^-2)^0

Mathematics

2 answers:

sergiy2304 [10]2 years ago

8 0

Answer:

$= - 3$

I have brainlest

I have follow me

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Alexxandr [17]2 years ago

8 0

The answer is -3 make them brainliest ^

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A toal of 21,650 balls. It sold 11,795 baseballs. It sold 4,150 fewer basketballs than baseballs. The rest of the balls sold wer

Lunna [17]

Answer: 5705 Footballs

Step-by-step explanation: Just subtract 11,795 by 4,150 to get the missing variable.

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3 years ago

The circumference of one of the smaller circles is 12pie cm. Find the circumference of the larger circle.. . A. 12pie cm. B. 24p

Temka [501]

There exists a similar question that would lead to the relationship of the given circumference to the unknown value. The radius of the larger circle is 12 cm. The formula for determining the circumference is,
C = 2πr
Substituting the known value,
C = 2π x 12 cm = 24π cm
Thus, the answer is letter B.

4 0

3 years ago

Wasn’t sure how to write this out : - )

amid [387]

we are given

$\frac{\sqrt[3]{7}\sqrt{7}}{\sqrt[6]{7^5}}$

we can write it in terms of exponents

$\frac{7^{\frac{1}{3}}*7^{\frac{1}{2}}}{7^{\frac{5}{6}}}$

Firstly , we will simplify numerator

$\frac{7^{\frac{1}{3}+\frac{1}{2}}}{7^{\frac{5}{6}}}$

now, we can add exponents

$\frac{7^{\frac{5}{6}}}{7^{\frac{5}{6}}}$

we can cancel it

and we get

$=1$ ............Answer

5 0

3 years ago

Shown is the graph for which of the following equations?

katrin2010 [14]

Since the graph is moving positive from left to right, x is positive. so now we are left with B) and C) for our answer

now, the y intercept or b is -3 as shown in the graph

the answer is C) y= x -3

8 0

3 years ago

Really need help guys!<br> Love you if you can solve them wiz steps!!!!

Marta_Voda [28]

Answer:

Step-by-step explanation:

$x^2+y^2-8x+4y+4=0\\\\a)\\\\x^2-8x+y^2+4y+4=0\\\\x^2-2*x*4+(y^2+2*y*2+2^2)=0\\\\x^2-2*x*4+4^2+(y+2)^2=4^2\\\\(x-4)^2+(y+2)^2=4^2\\$

Hence,

The radius of the circle is 4 units, coordinates of its centre are (4,-2).

$b)\\\\y=0\\x^2+0^2-8x+4*0+4=0\\x^2-8x+4=0\\a=1\ \ \ \ b=-8\ \ \ \ c=4\\D=(-8)^2-4*1*4\\D=64-14\\D=48\\\sqrt{D}=\sqrt{48} \\ \sqrt{D}=\sqrt{16*3} \\\sqrt{D}=\sqrt{4^2*3} \\\sqrt{D}=4\sqrt{3} \\\displaystyle\\x=\frac{-(-8)б4\sqrt{3} }{2*1} \\\\x=\frac{8б4\sqrt{3} }{2} \\x_1=4-2\sqrt{3} \\x_2=4+2\sqrt{3}$

$c)\\\\A(6,2\sqrt{3}-2)\\ (x-4)^2+(y+2)^2=4^2\\(6-4)^2+(2\sqrt{3} -2+2)^2=16\\2^2+(2\sqrt{3} )^2=16\\4+2^2*(\sqrt{3})^2=16\\ 4+4*3=16\\4+12=16\\16\equiv16$

$d)\\A(6,2\sqrt{3}-2)}\\\sqrt{3} x+3y=\\\sqrt{3}(6)+3(2\sqrt{3} -2)=\\ 6\sqrt{3}+6\sqrt{3} -6=\\ 12\sqrt{3}-6$

5 0

1 year ago