Yes, there is an expanded algorithm for synthetic division involving nonlinear and non-monic divisors (check out the w.i.k.i.pedia page on "synthetic division", under the "Expanded sythetic division" section).
Answer:
- number of multiplies is n!
- n=10, 3.6 ms
- n=15, 21.8 min
- n=20, 77.09 yr
- n=25, 4.9×10^8 yr
Step-by-step explanation:
Expansion of a 2×2 determinant requires 2 multiplications. Expansion of an n×n determinant multiplies each of the n elements of a row or column by its (n-1)×(n-1) cofactor determinant. Then the number of multiplies is ...
mpy[n] = n·mp[n-1]
mpy[2] = 2
So, ...
mpy[n] = n! . . . n ≥ 2
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If each multiplication takes 1 nanosecond, then a 10×10 matrix requires ...
10! × 10^-9 s ≈ 0.0036288 s ≈ 0.004 s . . . for 10×10
Then the larger matrices take ...
n=15, 15! × 10^-9 ≈ 1307.67 s ≈ 21.8 min
n=20, 20! × 10^-9 ≈ 2.4329×10^9 s ≈ 77.09 years
n=25, 25! × 10^-9 ≈ 1.55112×10^16 s ≈ 4.915×10^8 years
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For the shorter time periods (less than 100 years), we use 365.25 days per year.
For the longer time periods (more than 400 years), we use 365.2425 days per year.
Answer:
C. {-1, 5, 8}
Step-by-step explanation:
Use each of the domain values in the function to see what the corresponding range value is.
f(-1) = 5 -3(-1) = 8
f(0) = 5 -3(0) = 5
f(2) = 5 -3(2) = -1
The range is the set of numbers {-1, 5, 8}.
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<em>Additional comment</em>
The values in a set are generally listed lowest to highest. The coefficient of x in the equation for f(x) is negative, meaning the lowest range value will correspond to the highest domain value. If you start by finding f(2) = -1, you immediately eliminate all answer choices except B and C.
Those choices differ only in the middle value, so you can tell which is correct by evaluating f(x) for the middle domain value: f(0) = 5. Only one answer choice has both -1 and 5 in the set.
(There are two answers here: how you work the problem, and how you game a multiple choice question.)
Answer:
He eats 2 oz of candy every day.
Step-by-step explanation:
10oz divided by 5d equals 2 oz per day.
