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Darya [45]
3 years ago
12

F(x)=square root 5x+7, g(x)= square root 5x-7 Find (f+g)(x)

Mathematics
1 answer:
o-na [289]3 years ago
5 0

Answer: sqrt of 5x+7+ sqrt of 5x-7

Step-by-step explanation:

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Papessa [141]

Answer:

B

Step-by-step explanation:

10x3= 30

because kim spends 10 min washing her car, and Denzel spends 3 x as a many washing his car.

so you do 10 x 3 = 30

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What is 25/6 with remainder
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4 remainder 1 because six goes into twenty-five four times which is twenty-four and one more will make twenty five
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The length of a rectangle is 9 centimeters more than half
Sedaia [141]

Answer:

l = 16 cm

Step-by-step explanation:

Let's set the width of the rectangle as "w" and the length of the rectangle as "w/2 + 9".

The perimeter of a rectangle is calculated by adding up the value of all of its side lengths. Therefore, we can find the perimeter using 2l + 2w = P.

We can substitute 60 for P and w/2 + 9 for l.

  • 2(w/2 + 9) + 2w = 60
  • 2w/2 + 18 + 2w = 60
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Substitute w = 14 into the equation for length l.

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The length of the rectangle is 16 cm.

4 0
2 years ago
The Celsius temperature is 32 degrees. What is the Fahrenheit temperature
Aleksandr [31]

Answer:

89.6

Step-by-step explanation:

(32°C × 9/5) + 32 = 89.6°F

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Answer/step-by-step explanation

The soldier at point P lie on a parabola because he determined his position and distances from towns A and B through measurement of the difference in timing (phase) of radio signals received from the two towns.

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This process is known as hyperbolic navigation.

These distances of point P from towns A and B is estimated by the soldier at point P, by measuring the delay localizes the receiver to a hyperbolic line on a chart.

Two hyperbolic lines will be drawn by taking timing measurements from the

towns A and B .

Point P will be at the intersection of the lines.

These distances of point P(The soldier's positions) from town A and town B were determined using the timing of the signals received from the two towns, due to the fact that point P was on a certain hyperbola.

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