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Drupady [299]
2 years ago
9

Two cars got an oil change at the same auto shop. The shop charges customers for each quart of oil plus a flat fee for labor. Th

e oil change for one car required 5 quarts of oil and cost $24.80. The oil change for the other car required 7 quarts of oil and cost $29.30. How much is the labor fee and how much is each quart of oil?
Mathematics
1 answer:
zvonat [6]2 years ago
6 0

The labor fee is $13.55 and each quart of oil is $2.25

Step-by-step explanation:

Let,

x be the amount of each quart of oil

y be the amount of labor fee

According to given statement;

5x+y=24.80        Eqn 1

7x+y=29.30        Eqn 2

Subtracting Eqn 1 from Eqn 2

(7x+y)-(5x+y)=29.30-24.80\\7x+y-5x-y=4.50\\2x=4.50

Dividing both sides by 2

\frac{2x}{2}=\frac{4.50}{2}\\x=2.25

Putting x=2.25 in Eqn 1

5(2.25)+y=24.80\\11.25+y=24.80\\y=24.80-11.25\\y=13.55

The labor fee is $13.55 and each quart of oil is $2.25

Keywords: linear equation, subtraction

Learn more about subtraction at:

  • brainly.com/question/116715
  • brainly.com/question/11680012

#LearnwithBrainly

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madam [21]

Answer:

D.Place the compass on a point on the original line.

Complete Question:

A.Create only one arc that intersects the original line.

B.Create two arcs that intersect the original line.

C.Place the compass on a point off the original line.

D.Place the compass on a point on the original line.

Step-by-step explanation:

* Lets revise the steps of constructing parallel lines and a perpendicular line through a point on the line

<em># Contracting parallel lines</em>

- Given: Line AB and point P not on AB

1. Draw a slant line through point P and intersects AB at point C, this line is the transversal of the parallel lines

2.<u> Place the pin of the compass at point C</u> and draw an arc intersects AB at D and CP at E

3. Without changing the distance of the compass put the pin of the compass on point P and draw an arc intersects CP at point Q

4. Use the compass to measure the distance from D to E and place the pin of the compass at point Q and draw an arc intersects the arc from P to CP at point U

5. Join P and U by a line this line is parallel to AB

<em># Constructing a perpendicular line through a point on the line</em>

- Given line AB and point P lies on it

1. <u>Place your compass pin at P </u>and draw an arc of any size below AB that crosses the line twice at points C and D

2. Stretch the compass to a larger distance

3.<u> </u>Place the compass pin on point C<u> </u>and draw a small arc above the line

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5. Using a straightedge, join P and E where PE is perpendicular to AB

*<em> Lets find the same steps in the constructions</em>

∵ In first construction we put the pin of the compass at point C which  lies in the original line AB

∵ In second construction we put the pin of the compass at point P which lies in the original line AB

∴ The common step is:  <em><u>"Place the compass on a point on the original line"</u></em>

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2 years ago
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