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dsp73
2 years ago
10

Determine whether the relation is a function. c = {(10,3), (-10, – 3), (2, - 2). (3,- 10)}

Mathematics
2 answers:
Dovator [93]2 years ago
8 0

set x to set y to be a function if each member of set x pairs is exactly one member of set y

set x: 10, -10, 2, 3

set y: 3, -3, -2, -10

so the relation is a function

DIA [1.3K]2 years ago
5 0

Yes, it is a function, because no x value is repeated.

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2/8 greater or less than 1/2
suter [353]
Less than 
2/8=1/4
1/4 < 1/2

3 0
3 years ago
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Write the expanded from of h(3k-12.4)
rewona [7]

Answer:

3kh - 12.4h

Step-by-step explanation:

h(3k-12.4)

= h(3k) - h(12.4)

= 3kh - 12.4h

7 0
3 years ago
13 mm<br> 17 mm<br> What would the area of the triangle
Bad White [126]

Answer:

110.5mm

Step-by-step explanation:

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a = 13(17)/2

221/2 = 110.5

5 0
3 years ago
What is the equation of the quadratic graph with a focus of (-4,17/8) and a directrix of y=15/8
Temka [501]
So hmm notice the graph below

based on where the focus point is at, and the directrix, then, the parabola is opening upwards, meaning the squared variable is the "x"

\bf \begin{array}{llll}&#10;(y-{{ k}})^2=4{{ p}}(x-{{ h}}) \\\\&#10;\boxed{(x-{{ h}})^2=4{{ p}}(y-{{ k}})}\\&#10;\end{array}&#10;\qquad &#10;\begin{array}{llll}&#10;vertex\ ({{ h}},{{ k}})\\\\&#10;{{ p}}=\textit{distance from vertex to }\\&#10;\qquad \textit{ focus or directrix}&#10;\end{array}

now, keep in mind, the vertex is at coordinates h,k
the vertex itself is half-way between the focus and directrix
the directrix is at y=15/8 and the focus is at y=17/8
so, half-way will then be \bf \cfrac{17}{8}-\cfrac{15}{8}=\cfrac{2}{8}\iff \cfrac{1}{4}

well, so is 1/4 between the focus point and the directrix, half of that is 1/8
so, if you move from the focus point 1/8 down, you'll get the y-coordinate for the vertex, or 1/8 up from the directrix, since the vertex is equidistant to either

what's the "p" distance? well, we just found it, is just 1/8

so, the x-coordinate is obviously -4, get the y-coordinate by 17/8 - 1/8   or 15/8 + 1/8

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4 0
3 years ago
Solving Quadratic Equations using the Square Root Property
Afina-wow [57]

Answer:

x = -2   or   x = -5

Step-by-step explanation:

You need to complete the square before you can take the square root of both sides.

x^2 + 7x + 10 = 0

Subtract 10 from both sides.

x^2 + 7x = -10

To complete the square, you need to add the square of half of the x-term coefficient to both sides.

The x-term coefficient is 7. Half of that is 7/2. Square it to get 49/4. Now we add 49/4 to both sides of the equation.

x^2 + 7x + \dfrac{49}{4} = -10 + \dfrac{49}{4}

(x + \dfrac{7}{2})^2 = -\dfrac{40}{4} + \dfrac{49}{4}

(x + \dfrac{7}{2})^2 = \dfrac{9}{4}

Now we use the square root property, if

x^2 = k, then

x = \pm \sqrt{k}

x + \dfrac{7}{2} = \pm \sqrt{\dfrac{9}{4}}

x + \dfrac{7}{2} = \pm \dfrac{3}{2}

x + \dfrac{7}{2} = \dfrac{3}{2}   or   x + \dfrac{7}{2} = -\dfrac{3}{2}

x = -\dfrac{4}{2}   or   x = -\dfrac{10}{2}

x = -2   or   x = -5

5 0
3 years ago
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