Question

Factor by using the difference of two cubes (2x)³- 8 ​

Answer 1

Answer:

$(2x + 2)( {4x}^{2} - 4x + 4)$

Solution,

${(2x)}^{3} - 8$

$( {2x)}^{3} - {(2)}^{3}$

Use the formula:

${a}^{3} - {b}^{3} = (a + b)( {a}^{2} - ab + {b}^{2} )$

now,

$(2x + 2)( {(2x)}^{2} - 2x \times 2 + {(2)}^{2} )$

$(2x + 2)( {4x}^{2} - 4x + 4)$

Hope this helps...

Good luck on your assignment...