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2 years ago

Need help with math problem if do get 5 star

Mathematics

2 answers:

Rama09 [41]2 years ago

6 0

Answer:

a) 56 square units

Step-by-step explanation:

x = 3 (width - w)

y = 5 (base - b)

h = 7 (length and height - l and h)

Area of a rectangle: l*w
Area of a triangle: 1/2*b*h

For the triangles:

Area of a triangle: 1/2*b*h

A = 1/2 * 5 * 7

A = 1/2 * 35

A = 17.5

*Since there are two triangles, it would be 17.5 * 2 = 35

For the rectangle:

Area of a rectangle: l*w

A = 7 * 3

A = 21

Now, we add them together:

A = 35 + 21

A = 56 square units

Therefore, the area of the parallelogram is 56 square units

Hope this helps!

Alchen [17]2 years ago

4 0

Answer:

Option A. 56 square units

Step-by-step explanation:

Using the formula:

$A = \frac{1}{2}(a+b) h$ or $A = \frac{a+b}{2} h$

We substitute x with a and y with b:

x should be 3 units at the top, it has probably been cut off.

To work out b which should be the length at the bottom:

5+x+5 = 5+3+5 = 13

So b = 13

Now we substitute all values into the equation:

A = ((3+13)÷2)×7

A = (16÷2)×7

A = 8×7

A = 56

Therefore our answer is 56 square units

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Polygon ABCD is a rectangle what is the area

Andre45 [30]

Solution:

As, You have Written Polygon ABCD is a rectangle.

It is a Four sided Polygon , having all it's interior angles equal to 90°.As well as Opposite sides are equal(AB=CD,AD=BC), equal diagonals(AC=B D).

Join any of the diagonal of Rectangle either AC or B D.

In Right Δ ABC , Right angled at B

${\text{Area (Right triangle ABC)}} =\frac{1}{2}\times AB \times BC$ ---(1)

In Right Δ ADC , Right angled at D

${\text{Area (Right triangle ABC)}} =\frac{1}{2}\times AD \times DC$ ---(2)

Adding (1) and (2) that is LHS to LHS and RHS to RHS

Ar( Δ ABC) +Ar( Δ ADC) $=\frac{1}{2}\times[ AB \times BC+ AD \times DC]\\\\=\frac{1}{2}[2 \times AB \times BC][\text{As, AB=CD, and BC=AD}]\\\\ = AB \times BC$