Answer:
Let d be the remaining distance.
Let t be the remaining time.
The standard distance equation is:
d = rt
We are given the rate as 2, so:
d = 2t
At the start of the walk, the remaining distance is 3 miles.
The remaining time is 1.5 hours.
At the end of the walk, the remaining distance is 0 miles.
The remaining time is 0 hours.
A graph of the distance and time would be a continuous, solid line. That's because the walker will be at every distance between 3 and 0 and every time between 1.5 and 0.
Answer:
The graph of this would be a solid line
Hi there!
To solve, we must use the following trig identity:
sin(u - v) = sin(u)cos(v) - sin(v)cos(u)
We can rewrite the left hand side of the equation as:
Split the fraction:
First fraction reduces to 1:
Simpify each with common arguments:
Answer:
the answer is 0 to 1 and 3 to 4
Answer:
16.852
Step-by-step explanation:
All side lengths are the same in an octagon. What you do is take the diamater and multiply it by 0.383. Diamater is the radius doubled.
<span>If this is an isosceles triangle, then it has two 45 degree angles corresponding to two legs of equal length. Orient the base of this triangle so that it's horizontal, and represent its length by b. Let h represent the height of the triangle. Then the area of this right triangle is 50 square inches = (1/2)(b)(h), or A = (b/2)h = 50 in^2.
Due to the 45 degree angles, the height of this triangle is equal to half the base, or h = b/2. Thus, (b/2)h = 50 becomes (b/2)(b/2) = 50, or b^2=200. Thus, b = 10sqrt(2), and h=(1/2)(10 sqrt(2)), or h = 5sqrt(2).
The length of one of the legs is the sqrt of [5sqrt(2)]^2+[5sqrt(2)]^2, or
sqrt(25(2)+25(2)) = sqrt(100) = 10.
</span>
