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denis-greek [22]
2 years ago
11

If $25, 000 is invested into an account paying 4.5% per year, compounded quarterly, how much money can be withdrawn from the acc

ount every two months for the next 6 years?
Mathematics
1 answer:
pogonyaev2 years ago
7 0

The money can be withdrawn from the account every two months for the next 6 years is $20, 625, 000

<h3>What is compound interest?</h3>

The formula for compound interest is given as;

A = P ( 1 + \frac{r}{n} )^n^t

P = principal interest = $25, 000

r = rate = 4. 5%

n = 2 months

t = 6 years

A = 25, 000 ( 1 + \frac{4. 5}{2} )^2 ^*^6

A = 25, 000(1 + 0. 75)^1^2

A = 25, 000( 825. 00)

A = $20, 625, 000

Thus, the money can be withdrawn from the account every two months for the next 6 years is $20, 625, 000

Learn more about compound interest here:

brainly.com/question/2455673

#SPJ1

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P (6,6) y=2/3x
matrenka [14]

Answer:

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Step-by-step explanation:

Given:

Given point P(6, 6)

The equation of the line.

y = \frac{2}{3}x

We need to find the equation of the line perpendicular to the given line that contains P

Solution:

The equation of the line.

y = \frac{2}{3}x

Now, we compare the given equation by standard form y = mx +c

So, slope of the line m_{1} = \frac{2}{3}, and

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We know that the slope of the perpendicular line m_{1}\times m_{2}  = -1

m_{2}=-\frac{1}{m_{1}}

m_{2}=-\frac{1}{\frac{2}{3} }

m_{2}=-\frac{3}{2}

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From the above statement, line passes through the point P(6, 6).

Using slope intercept formula to know y-intercept.

y=mx+c

Substitute point P(x_{1}, y_{1})=P(6, 6) and m = m_{2}=-\frac{3}{2}

6=-\frac{3}{2}\times 6 +c

6=-3\times 3 +c

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c=15

So, the y-intercept of the perpendicular line c=15

Using point slope formula.

y=mx+c

Substitute m = m_{2}=-\frac{3}{2} and c=15 in above equation.

y = -\frac{3}{2}x+15

Therefore: the equation of the perpendicular line y = -\frac{3}{2}x+15

8 0
3 years ago
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solniwko [45]
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4 0
3 years ago
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Serggg [28]

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Step-by-step explanation:

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Answer:

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