Question

Help please Im giving brianless and 100 points to the person who answer and show their work thank you very much

Answer 1

• Base=35-9-12.5=12.5ft=B
• Perpendicular=p
• \theta= 16.5°

Now

$\\ \rm\Rrightarrow tan\theta=\dfrac{P}{B}$

$\\ \rm\Rrightarrow tan16.5=\dfrac{P}{13.5}$

$\\ \rm\Rrightarrow P=13.5tan16.5$

$\\ \rm\Rrightarrow P=13.5(0.3)$

$\\ \rm\Rrightarrow P\approx 4ft$

Answer 2

Answer:

8.5 ft (nearest tenth)

Step-by-step explanation:

To find the depth of the pool at the deep end, we need to find the height of the right triangle with angle 16.5° and add it to 4.5 ft

Base of the triangle = 35 - 9 - 12.5 = 13.5 ft

Use the tan trig ratio:

$\tan(x)=\dfrac{O}{A}$

where x is the angle, O is the side opposite and angle and A is the side adjacent to the angle in a right triangle.

Given:

• x = 16.5°
• O = h (height)
• A = 13.5 ft

$\implies\tan(16.5)=\dfrac{h}{13.5}\\\\\implies h= 13.5\tan(16.5)\\\\\implies h = 4.0 \textsf{ ft (nearest tenth)}$

Therefore, the depth of the pool at the deepest end = 4 + 4.5 = 8.5 ft (nearest tenth)