Given:
The polynomial is
To find:
The real and complex zeros of the equation.
Solution:
We have,
For zeros, p(x)=0.
The real value of x is 0. The equation 
will give complex roots. Here, a=1, b=-2 and c=2.
Using quadratic formula, we get
On further simplification, we get
Therefore, the real zero is 0 and the complex zeros are 1+i and 1-i.
Step-by-step explanation:
→ 7m – q = 23
- q subtracted from 7 times m is equivalent to 23.
Answer:
Step-by-step explanation:
"quaratic" should be "quadratic."
The coefficients of this quadratic are 4, 2 and -1. Thus, the discriminant is
b^2 - 4ac, or here, 4 - 4(4)(-1) = 20
Since the discriminant is positive, our quadratic has two real, different roots.
-2 ± (√4)(√5)
The roots are: x = ---------------------
2(4)
-1 ± √5
This reduces to x = ---------------
8
Divide 3.392 by 32 =.106 is the length because width X length = area
