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Dafna11 [192]
3 years ago
5

4x^2+2x-1=0 in quaratic equations

Mathematics
1 answer:
Viktor [21]3 years ago
5 0

Answer:

Step-by-step explanation:

"quaratic" should be "quadratic."

The coefficients of this quadratic are 4, 2 and -1.  Thus, the discriminant is

b^2 - 4ac, or here, 4 - 4(4)(-1) = 20

Since the discriminant is positive, our quadratic has two real, different roots.

                                -2 ± (√4)(√5)

The roots are:  x = ---------------------

                                       2(4)

                                    -1 ± √5

This reduces to   x = ---------------

                                           8

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Can someone pretty please help meeee! WILL GIVE BRAINLIEST!
krok68 [10]
Is this supposed to be middle school math-
7 0
3 years ago
SOMEONE PLSSS HELPPP
podryga [215]

Answer:

  d  Dilation by a scale factor of 2 followed by reflection about the y-axis

Step-by-step explanation:

In each case, the transformation is ...

  (x, y) ⇒ (-2x, 2y)

So, a dilation by a factor of 2 is involved. That is what multiplies the coordinates by 2. Reflection in the y-axis is what negates the x-coordinate.

The transformations are ...

  Dilation by a scale factor of 2 followed by reflection about the y-axis

8 0
4 years ago
What are the ratios of 7 and 23
asambeis [7]

Answer:

7 / 23 or 30.434782608696%

Step-by-step explanation:

If you mean the 7 to 23 ratio, then this is the answer

5 0
4 years ago
Read 2 more answers
I can't seem to figure this one out, this is all the info that was given:
vazorg [7]

Answer:

4a + 4

Step-by-step explanation:

f(x) = x² + 2

f(a) = a² + 2

f(a+2) = (a+2)² + 2

f(a+2) − f(a) = (a+2)² + 2 − (a² + 2)

f(a+2) − f(a) = a² + 4a + 4 + 2 − a² − 2

f(a+2) − f(a) = 4a + 4

7 0
3 years ago
What is the 31st term of the arithmetic sequence for 1.77, 1.92,2.07
natita [175]

Given that sequence 1.77, 1.92,2.07 is arithmetic sequence.

Using that we have to find 31st term.

To find that we can use nth term formula of arithmetic sequence which is given by:

t_n=a_1+(n-1)d

where n is the number of term so n=31

t_n indicates nth term

a_1 is the first term so a_1=1.77

r is the common difference which is given by difference of consecutive terms

then r=1.92-1.77=0.15

Now plug these values into above formula


t_n=a_1+(n-1)d

t_{31}=1.77+(31-1)*0.15

t_{31}=1.77+(30)*0.15

t_{31}=1.77+4.5

t_{31}=6.27


Hence final answer is 6.27.

8 0
4 years ago
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