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1 year ago

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4. A town has a population of 450,000 people. If 60% of the population are under 25 years of age, how many people in the town ar

e 25 years old and over?

1 answer:

lesya [120]1 year ago

5 0

Answer: <em>ok so if 60% is under 25 then we can assume 40% is over 25, and then do 40% of 450,000, which is 180,000 .</em>

<em>so we can say that 180,000 people in the town are over 25 years old</em>

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3 years ago

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2 years ago

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The indicated probability of $P(D \cup F')=\frac{25}{26}$

Step-by-step explanation:

Probability of an event E to be;

P(E) = $\frac{Number of events within E}{Total number of possible outcomes}$

As per the given condition:

Total number of possible outcomes = 52 cards.

Let the event be D and F as follows;

D : Drawn card is a black card

F : Drawn card is a 10 card.

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From the given condition:

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P(F) = $\frac{4}{52}$ [Out of 52 cards, there are four 10 cards]

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$P(A \cup B) = P(A)+P(B)-P(A \cap B)$

Now, we have to find the indicated probability:

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P(F') =1-P(F) = $1-\frac{4}{52} =\frac{52-4}{52} =\frac{48}{52}$

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We use the formula :

For any event A and B independent variable.

$P(A \cap B) =P(A) \cdot P(B)$

then;

$P(D \cap F') =P(D) \cdot P(F') = \frac{26}{52} \cdot \frac{48}{52} =\frac{24}{52}$

Now, substitute these in [1];

$P(D \cup F')=\frac{26}{52} +\frac{48}{52} -\frac{24}{52}$ = $\frac{26+48-24}{52} =\frac{50}{52} = \frac{25}{26}$

Therefore, the probability of $P(D \cup F')=\frac{25}{26}$

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