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2 years ago

I need help again yall

Mathematics

2 answers:

12345 [234]2 years ago

6 0

Answer: 4z + 28

Step-by-step explanation:

We can distribute the 4 to each term inside the parenthesis.

So 4(z+7) = 4*z + 4*7

= 4z + 28

Mrrafil [7]2 years ago

6 0

Step-by-step explanation:

4(z + 7) = 4×z + 4×7 = 4z + 28

sorry, but this is so simple. so, what do you not understand about that yet ?

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Need help with all this

Inessa [10]

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

Hello!

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

❖ To find the mean, add up all the numbers and divide by the amount of numbers there are. To find the range, subtract the highest number by the lowest number in the data set.

2. Mean = 35 Range = 78

3. Mean = 43 Range = 58

4. Mean = 63 Range = 73

5. Mean = 61 Range = 56

6. Mean = 55 Range = 83

7. Mean = 61 Range = 53

8. Mean = 60 Range = 75

9. Mean = 50 Range = 76

10. Mean = 50 Range = 81

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

7 0

3 years ago

4. Which value for x makes the sentence true? 3x - 8 = 16 x=

zzz [600]

Answer: x = 8

Step-by-step explanation:

This is a very, very, very simple algebra problem. I assume you know the basics of algebra.

First, move 8 to the other side:

3x = 24

divide by 3 on both sides

x = 8

There! Would it kill you to give me a quartic question to spice my life up?

4 0

1 year ago

Read 2 more answers

For the figure, which of the following is true? I. m∠1+m∠2=m∠6+m∠5 II. m∠1+m∠3=m∠6+m∠4 III. m∠1+m∠3+m∠6=m∠2+m∠4+m∠5 A. I only B.

Alexxx [7]

Yea the answers 9!!!!!!

3 0

3 years ago

PLEASE HELP ME. I WILL GIVE GIVE YOU BRAINLIEST. But only if the answers are correct

-Dominant- [34]

Answer:

12 I wanna say!!!!!!!!!!!!

8 0

3 years ago

Read 2 more answers

Suppose that a basketball player can score on a particular shot with probability .3. Use the central limit theorem to find the a

Rom4ik [11]

Answer:

(a) The probability that the number of successes is at most 5 is 0.1379.

(b) The probability that the number of successes is at most 5 is 0.1379.

(d) The probability that the number of successes is at most 11 is 0.9357.

→ All the exact probabilities are more than the approximated probability.

Step-by-step explanation:

Let S = a basketball player scores a shot.

The probability that a basketball player scores a shot is, P (S) = p = 0.30.

The number of sample selected is, n = 25.

The random variable $S\sim Bin(25,0.30)$

According to the central limit theorem if the sample taken from an unknown population is large then the sampling distribution of the sample proportion ( $\hat p$ ) follows a normal distribution.

The mean of the the sampling distribution of the sample proportion is: $E(\hat p)=p=0.30$

The standard deviation of the the sampling distribution of the sample proportion is:

$SD(\hat p)=\sqrt{\frac{ p(1- p)}{n} }=\sqrt{\frac{ 0.30(1-0.30)}{25} }=0.092$

(a)

Compute the probability that the number of successes is at most 5 as follows:

The probability of 5 successes is: $p=\frac{5}{25} =0.20$

$P(\hat p\leq 0.20)=P(\frac{\hat p-E(\hat p)}{SD(\hat p)}\leq \frac{0.20-0.30}{0.092} )\\=P(Z\leq -1.087)\\=1-P(Z$

**Use the standard normal table for probability.

Thus, the probability that the number of successes is at most 5 is 0.1379.

The exact probability that the number of successes is at most 5 is:

$P(S\leq 5)={25\choose 5}(0.30)^{5}91-0.30)^{25-5}=0.1935$

The exact probability is more than the approximated probability.

(b)

Compute the probability that the number of successes is at most 7 as follows:

The probability of 5 successes is: $p=\frac{7}{25} =0.28$

$P(\hat p\leq 0.28)=P(\frac{\hat p-E(\hat p)}{SD(\hat p)}\leq \frac{0.28-0.30}{0.092} )\\=P(Z\leq -0.2174)\\=1-P(Z$

**Use the standard normal table for probability.

Thus, the probability that the number of successes is at most 7 is 0.4129.

The exact probability that the number of successes is at most 7 is:

$P(S\leq 57)={25\choose 7}(0.30)^{7}91-0.30)^{25-7}=0.5118$

The exact probability is more than the approximated probability.

(c)

Compute the probability that the number of successes is at most 9 as follows:

The probability of 5 successes is: $p=\frac{9}{25} =0.36$

$P(\hat p\leq 0.36)=P(\frac{\hat p-E(\hat p)}{SD(\hat p)}\leq \frac{0.36-0.30}{0.092} )\\=P(Z\leq 0.6522)\\=0.7422$

**Use the standard normal table for probability.

Thus, the probability that the number of successes is at most 9 is 0.7422.

The exact probability that the number of successes is at most 9 is:

$P(S\leq 9)={25\choose 9}(0.30)^{9}91-0.30)^{25-9}=0.8106$

The exact probability is more than the approximated probability.

(d)

Compute the probability that the number of successes is at most 11 as follows:

The probability of 5 successes is: $p=\frac{11}{25} =0.44$

$P(\hat p\leq 0.44)=P(\frac{\hat p-E(\hat p)}{SD(\hat p)}\leq \frac{0.44-0.30}{0.092} )\\=P(Z\leq 1.522)\\=0.9357$

**Use the standard normal table for probability.

Thus, the probability that the number of successes is at most 11 is 0.9357.

The exact probability that the number of successes is at most 11 is:

$P(S\leq 11)={25\choose 11}(0.30)^{11}91-0.30)^{25-11}=0.9558$

The exact probability is more than the approximated probability.

6 0

3 years ago