One is colder than the other.
Hope this helps :)
Cosine(O) = Adj / Hypo
Plug in numbers to find the ratio
Hope it helps
Y is equal to 1 because to change 15 into 5 you have to divide by 3. 15/3=5. So you do the same to the other coordinate. Divide 3 by 3 to get 1.
Answer:
<em>The largest rectangle of perimeter 182 is a square of side 45.5</em>
Step-by-step explanation:
<u>Maximization Using Derivatives</u>
The procedure consists in finding an appropriate function that depends on only one variable. Then, the first derivative of the function will be found, equated to 0 and find the maximum or minimum values.
Suppose we have a rectangle of dimensions x and y. The area of that rectangle is:
![A=x.y](https://tex.z-dn.net/?f=A%3Dx.y)
And the perimeter is
![P=2x+2y](https://tex.z-dn.net/?f=P%3D2x%2B2y)
We know the perimeter is 182, thus
![2x+2y=182](https://tex.z-dn.net/?f=2x%2B2y%3D182)
Simplifying
![x+y=91](https://tex.z-dn.net/?f=x%2By%3D91)
Solving for y
![y=91-x](https://tex.z-dn.net/?f=y%3D91-x)
The area is
![A=x.(91-x)=91x-x^2](https://tex.z-dn.net/?f=A%3Dx.%2891-x%29%3D91x-x%5E2)
Taking the derivative:
![A'=91-2x](https://tex.z-dn.net/?f=A%27%3D91-2x)
Equating to 0
![91-2x=0](https://tex.z-dn.net/?f=91-2x%3D0)
Solving
![x=91/2=45.5](https://tex.z-dn.net/?f=x%3D91%2F2%3D45.5)
Finding y
![y=91-x=45.5](https://tex.z-dn.net/?f=y%3D91-x%3D45.5)
The largest rectangle of perimeter 182 is a square of side 45.5