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VMariaS [17]
3 years ago
11

3 consecutive integers is 183?

Mathematics
1 answer:
kotegsom [21]3 years ago
7 0

Answer:

set variables

Step-by-step explanation:

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if the sum of the first 60 positive integers is s, what is the sum of the first 120 integers in terms of s? a. 2s 3600 b. s^2 36
natima [27]
For the first 60 positive integers, a = 1, n = 60, l = 60.
Sn = n/2(a + l)
s = 60/2(1 + 60) = 30(61)

For the next 60 positive integer, a = 61, n = 60, l = 120
Sum = 60/2(61 + 120) = 30(61 + 120) = 30(61) + 30(120) = s + 3600

Sum of first 120 positive integers = s + s + 3600 = 2s + 3600
3 0
3 years ago
Pls give two answers for good measure
katrin2010 [14]

Step-by-step explanation: To solve for x in this inequality,

your goal is the same as it would be if you were solving an

equation, to get x by itself on one side.

Since 5 is being subtracted from x, add 5 to both sides of the inequality.

On the left, the -5and +5 cancel out and on the right, -2 + 5 is 3.

So we have x ≥ 3.

When graphing, start with a closed dot at +3 because x is

not just greater than +3, it's equal to it as well.

Then draw an arrow to the right, like I have done below.

8 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIEST!!!!!!!!!!!
lana [24]
I’m not completely sure about the answers but i can say this: every month adrienne get 5 new dollars. so if it was at like 2 months and $10 (for example) the next month (month 3) she would have $15
5 0
3 years ago
Rewrite the equation in Ax+By=C form.<br> Use integers for A, B, and C.<br> y-1=6(x + 2)
masha68 [24]

Answer:

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Find the equation of the tangent line to the curve y equals left parenthesis x minus 3 right parenthesis superscript 7 baseline
Rashid [163]

We have been given the expression to be y=(x-3)^7(x+1)^2

Since we need to find the tangent at a point, we will have to find the derivative of y as the slope of the tangent at a given point on the curve is always equal to value of the derivative at that point.

Thus, we have to find \frac{dy}{dx}=\frac{d}{dx} (x-3)^7(x+1)^2

We will use the product rule of derivatives to find \frac{dy}{dx}

Thus, y'=7(x-3)^6(x+1)^2+(x-3)^7\times2(x+1) (using the product rule which states that (fg)'=f'g+fg')

Taking the common factors out we get:

y'=(x-3)^6(x+1)(7(x+1)+2(x-3))

y'=(x-3)^6(x+1)(7x+7+2x-6)=(x-3)^6(x+1)(9x+1)

Thus, y' at x=4 is given by:

y'_{x=4}=Slope of the tangent of y at x=4=m

Thus, m=(4-3)^6(4+1)(9\times4+1)=185

Now, the equation of the tangent line which passes through (x_{1}, y_{1}) and has slope m is given by:

y-y_{1}=m(x-x_{1})

Thus, the equation of the tangent line which passes through (4,25) and has the slope 185 isy-25=185(x-4)

Which can be simplified to y=185x-740+25=185x-715

Thus, y=185x-715

This is the required equation of the tangent.

3 0
3 years ago
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