Answer:
And if we solve for a we got
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
Let X the random variable that represent the hourly rates of a population, and for this case we know the distribution for X is given by:
For this part we want to find a value a, such that we satisfy this condition:
(a)
(b)
Both conditions are equivalent on this case. We can use the z score again in order to find the value a.
As we can see on the figure attached the z value that satisfy the condition with 0.80 of the area on the left and 0.20 of the area on the right it's z=0.842. On this case P(Z<0.842)=0.8 and P(z>0.842)=0.20
If we use condition (b) from previous we have this:
But we know which value of z satisfy the previous equation so then we can do this:
And if we solve for a we got
Answer:
y = -2.8x +69.4
Step-by-step explanation:
The 2-point form of the equation of a line can be used to find the equation of the line through points (3, 61) and (13, 33). The general form of it is ...
y = (y2-y1)/(x2-x1)·(x -x1) +y1
For the given points, this is ...
y = (33 -61)/(13 -3)·(x -3) +61
y = -28/10(x -3) +61
y = -2.8x +69.4 . . . . . the equation of the line through the given points
_____
<em>Comment on the problem</em>
A "line of best fit" is one that minimizes some measure of deviation from the line. Usually, what is minimized is the square of the deviations. Choosing two points to draw the line through may be convenient, but does not necessarily result in a line of best fit.
12xy i think lol :) hope that helps a bit
Answer:
a) 5.13beats/min
b) 2.82 beats/min
Step-by-step explanation:
Given the pulse rate of a person modelled by the equation y = 600x^-1/3 for 30≤x≤75
If the height is 39inches, the instantaneous rate of change of pulse rate for the heights will be expressed as;
y = 600(39)^-1/3
y = {600(1/39)}/3
y = 600/39×3
y = 600/117
y ≈ 5.13beats/min
The instantaneous rate for a 39 inches tall person is 5.13 beats per min
b) For a 71inches tall person, the beat rate will be expressed as;
y = 600(71)^-1/3
y = {600(1/71)}/3
y = 600/71×3
y = 600/213
y ≈ 2.82 beats per minute
The instantaneous rate for a 71 inches tall person is 2.82 beats per min
Work shown above! Hopefully this is what you were looking for
