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2 years ago

The graphs below have the same shape. What is the equation of the blue

Mathematics

2 answers:

cluponka [151]2 years ago

7 0

Answer: The correct option is B.

Explanation:

From the given figure it is noticed that the parent function is,

$f(x)=x^2$

The graph of f(x) shifts 5 units right.

The transformation is defined as,

$g(x)=f(x+a)+b$

Where, a shows the horizontal shifts and b shows the vertical shift.

If a<0 then the graph of f(x) shifts right side by a units and if a>0 then the graph of f(x) shifts left side by a units.

If b<0 then the graph of f(x) shifts downward by b units and if b>0 then the graph of f(x) shifts upward by b units.

Since the graph of parent function is shifts only right side by 5 units, therefore

$g(x)=f(x-5)+0$

Since $f(x)=x^2$

$g(x)=(x+5)^2$

Thus, the correct option is B.

The function in option A represents the left shift of f(x) by 5 units. The option C represents the downward shift of f(x) by 5 units. The option D represents the upward shift of f(x) by 5 units.

frutty [35]2 years ago

4 0

Using a graph tool
see the attache figure

the answer is the option B
g(x)=(x-5)²

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In the figure below, ∠DEC ≅ ∠DCE, ∠B ≅ ∠F, and segment DF is congruent to segment BD . Point C is the point of intersection betw

Rzqust [24]

Answer:

Step-by-step explanation:

Given:

∠DCE ≅ ∠DEC

∠B ≅ ∠F

DF ≅ BD

To prove:

ΔABC ≅ ΔGFE

Solution:

Statements Reasons

1). ∠DCE ≅ ∠DEC 1). Given

2). ∠ACB ≅ ∠GEF 2). Vertically opposite angles to the

congruent angles.

3). ∠B ≅ ∠F 3). Given

4). DB ≅ DF 4). Given

5). DC + CB ≅ DE + EF 5). Segment addition postulate

6). DC ≅ DE 6). Property of isosceles triangle

7). CB ≅ EF 7). Transitive property

8). ΔABC ≅ ΔGFE 8). ASA property of congruence

4 0

2 years ago

Evaluate the following expression if y = 4

sleet_krkn [62]

15+5•y/2

15+5•4 / 2

15+20 / 2

15+10

=25

3 0

2 years ago

Pls help brainlist pls help

Len [333]

Answer:

1. V = 157in³, so the volume of the sugar container is 157in³

2. h = 12in, so the height of the rice container is 12in

3. The rice container's height is 12in and the height of the sugar container is 8in, which means the rice container is taller by 4in. The rice container's volume is 235.5in and the sugar container's volume is 157in, so the rice container's volume is greater than the volume of the sugar container's volume by 78.5in.

4. V = 50.24in³, so the volume of the flour container is 50.24in³

5. The rice container's volume is 235.5in, the sugar container's volume is 157in, and the flour container's volume is 50.24in. This means the container that contains the greatest volume is the rice container and the container that contains the smallest volume is the flour container.

Step-by-step explanation:

1. to find the volume of a cylinder, we use the formula:

V = πr²h

V = 3.14(2.5² × 8)

V = 3.14(6.25 × 8)

V = 3.14(50)

V = 157in³

2. To find the height of a cylinder when given the volume and radius, you use the formula:

h = V / πr²

h = 235.5/3.14(2.5²)

h = 235.5/3.14(6.25)

h = 235.5/19.625

h = 12in

h = height

V = bh

V = 12.56 × 4

V = 50.24in³

5 0

2 years ago

HELP MUTIPLE CHICE IM BEING TIMED GEOMETRY PICKING SOMEONE FOR Brainliest

ollegr [7]

Answer:

1. SSS

2. Q and S

3. 20

Step-by-step explanation:

1. SSS similarity: If the corresponding sides of two triangles are proportional, then the two triangles are similar.

Triangles NLM and WUV are similar by SSS similarity, because

$\dfrac{NL}{WU}=\dfrac{36}{63}=\dfrac{4}{7}\\ \\\dfrac{LM}{UV}=\dfrac{40}{70}=\dfrac{4}{7}\\ \\\dfrac{NM}{WV}=\dfrac{24}{42}=\dfrac{4}{7}$

2. Completed steps:

a) draw a circle with center at P and radius r

b) draw a circle with center at Q and radius r

c) using compass, measure the distance between two points of intersection of the first circle with angle rays

d) using point of intersection of the second circle with PQ as a center, draw the circle of radius equal to the distance from c) to get point S

Last step: connect points Q and S, line QS will be parallel to line r.

3. If lines MN and UT are parallel, then angles MUT and VMN are congruent; also angles UTN and MNV are congruent.

AA similarity: In two triangles, if two pairs of corresponding angles are congruent, then the triangles are similar .

By AA similarity, triangles VMN and VUT are similar, thus

$\dfrac{VM}{VU}=\dfrac{VN}{VT}\\ \\\dfrac{VM}{VM+8}=\dfrac{49-14}{49}\\ \\49VM=35(VM+8)\\ \\49VM=35VM+280\\ \\49VM-35VM=280\\ \\14VM=280\\ \\VM=20\ units$

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2 years ago

PÕQ = 40°? [WAEC] A pie chart is divided into four sectors as shown in Fig. 12.46. Each sector represents a percentage of the wh

Serhud [2]

Answer:

126°

Step-by-step explanation:

the total max percent can be 100%

The total value of the pie is 100%

that means all sectors must add upto 100

=> x + x + 21 + 9 = 100

=> 2x + 30 = 100

=> 2x = 70

=> x = 35

therefore, the two large sectors which are both equal to x each represents 35% of the whole.

<u>Angle subtended by one of those large sectors</u> :-

$\theta = \frac{component \: part}{total} \times 360$

$= \frac{35}{100} \times 360 \\ = 126$

therfore, the central angle of the big sector is<u> 126°</u>

6 0

3 years ago