Answer:
X=1
Step-by-step explanation:
1=5x-4
5=5x
5/5=5/5x
X=1
Step One is to add up all the values
6.5+5+6+5.5+7+4+4.5+5+6+5.5+4+7.5+6+7+8+5+6+6.5+6.5+5 = 116.5
Step Two is to divide the result from step one by 20 (since there are 20 values added up)
116.5/20 = 5.825
The sample mean is 5.825
1.A.
The base lengths of the trapezoid are 35cm and 19cm. The height is 15cm.
1.B.
The formula for the area of a trapezoid is
A=(b1+b2)/2*h
plug in the data we know
A=(35+19)/2*15
A=54/2*15
A=27*15
A=405cm²
since there are two trapezoids, we double that number 405*2=810cm²
Answer=810cm²
1.C.
To solve for this, we need to find the perimeter of the trapezoid
P=35+19+17+17=88cm
Answer=No. The edges of the trapezoid are longer than 80cm.
2.A.
3units. Since their x values are the same, you just subtract the y values to calculate distance 5-2=3
Answer=3
2.B
A right triangle. Since one coordinate is directly above, and the other is directly to the right of the bench
3.A
The two triangles would be...
A=1/2b*h=1/2*30*72=15*72=1080ft² each
and the center rectangle would be
A=l*w=20*72=1440ft²
Add them all together and you get
Total area=3600ft²
This is the derivative of S with respect to r, evaluated at r=8.
dS/dr = 8πr
Substituting r=8 into the above gives the answer of 64π.
