Answer:
in steps
Step-by-step explanation:
The question did not state if alpha>beta or alpha<beta, so the answer will have 2 answers for each questions
3x²-9x+2=0
x = (-(-9) ± √(-9)²-4*(3)*(2)) / (2*3)
x = (9 + √57) / 6 or x = (9 - √57) / 6 (alpha and beta) or (beta and alpha)
(I) alpha (a) ×beta (b) + alpha² × beta = ab (1+a)
= ((9 + √57) / 6) ((9 - √57) / 6) (1 + (9 ± √57))
= ((9² - (√57)²)/36) (10 ± √57)
= (24/36) (10 ± √57)
= 2/3 (10 ± √57) or (11.7 or 1.63)
(ii) alpha²-alpha×beta+beta² = a² -2ab + b² +ab = (a - b)² + ab
if a is alpha
= ((9 + √57) / 6) - ((9 - √57) / 6)) + ((9 + √57) / 6) ((9 - √57) / 6))
= √57/3 + 2/3
= (√57 + 2) / 3
if a is beta
((9 - √57) / 6) - ((9 + √57) / 6)) + ((9 - √57) / 6) ((9 + √57) / 6))
= - √57/3 + 2/3
= - (√57 + 2) / 3
Answer:
The answer to your question is: 1
Step-by-step explanation:
f(0) = 1 , because when x = 1, y = 1
Answer:
10
Step-by-step explanation:
if you add 5.5 + 5.5 together its 10
Answer:
360 learners
Step-by-step explanation:
One way to solve these types of problems is that you could set up a proportion
learners/teachers = learners/teachers
Let x = no. of learners to enrol
30/1 = x/12
12(30) = x
x = 360 learners
Answer:Yes, he is correct
Step-by-step explanation:Plug 6 in as your x-value in the equation y=-275x+3500 and you will get y=1850
