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Scilla [17]
3 years ago
10

What is a an output device

Computers and Technology
1 answer:
wel3 years ago
6 0

Answer:

<em>Any</em><em> </em><em>pie</em><em>ce</em><em> </em><em>of</em><em> </em><em>comp</em><em>uter</em><em> </em><em>hard</em><em>ware</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

You might be interested in
question 2 what are some types of software that you'd want to have an explicit application policy for? check all that apply.
zaharov [31]

The types of software that you'd want to have an explicit application policy are:

  • Filesharing software
  • video games

  • Explicit application policy are simply refered to as legal rights that are stated regarding ownership or company. It is actual substance of an agreement

  • Video games and filesharing software is of not really important in som business. So therefore, having explicit policies showing why or not this type of software is permitted on systems is okay.

Conclusively, we can say that Filesharing software and video games can require an explicit application policy.

Learn more from

brainly.com/question/12730075

4 0
3 years ago
Define a member function PrintAll() for class PetData that prints output as follows. Hint: Make use of the base class' PrintAll(
PilotLPTM [1.2K]

Answer:

Following are the program in the C++ Programming Language.

//set header file

#include <iostream>

//set header file for string

#include <string>

//set namespace

using namespace std;

//define class

class AnimalData

{

//set access modifier

public:

//define function

void SetName(string givenName)

{

//initialize the value of function's argument

fullName = givenName;

};

//define function

void SetAge(int numYears)

{

//initialize the value of function's argument

ageYears = numYears;

};  

//here is the solution

//define function

void PrintAll()

{

//print output with message

cout << "Name: " << fullName<<endl;

//print output with message

cout << "Age: " << ageYears<<endl;

};

//set access modifier

private:

//set integer data type variable

int ageYears;

//set string data type variable

string fullName;

};

//define class and inherit the parent class

class PetData: public AnimalData

{

//set access modifier

public:

//define function

void SetID(int petID)

{

idNum = petID;

};

//override the function for print id

void PrintAll()

{

AnimalData::PrintAll();

cout << "ID: " <<idNum ;

};

//set access modifier

private:

//set integer type variables

int idNum,fullName,ageYears;

};

//define main method

int main()

{

//create object of the child class

PetData userPet;

//call function through object

userPet.SetName("Fluffy");

//call function through object

userPet.SetAge (5);

//call function through object

userPet.SetID (4444);

//call function through object

userPet.PrintAll();

cout << endl;

return 0;

}

<u>Output</u>:

Name: Fluffy

Age: 5

ID: 4444

Explanation:

<u>Following are the description of the program</u>:

  • Set required header file and namespace.
  • Define class 'AnimalData' and inside the class, set integer data type variable 'ageYears', string data type variable 'fullName'.
  1. Then, define function 'SetName()' with string data type argument 'givenName' and initialize the value of argument in the string variable.
  2. Then, define function 'SetAge()' with integer data type argument 'numYears' and initialize the value of the argument in the integer variable.
  3. Define function 'PrintAll()' to print the value of the following variables with message.
  • Define class 'PetData' and inherit the parent class in it, then set integer data type variable 'idNum'.
  1. Then, define function 'SetID()' with integer data type argument 'petID' and initialize the value of the argument in the integer variable.
  2. Override the function 'PrintAll()' to print the value of the following variable with message.

Finally, define main method and create the object of the child class, then call the following functions through the class object.

8 0
3 years ago
The original commercial version of Ethernet supported 10 Mbps bandwidth; the version introduced in the early 1990s supports 100
Elodia [21]

Answer: a) and c).

Explanation:

  • Ethernet is a Layer 2 and also Layer 1 Technology (this layer defines the technical details of cabling and connectors), so any upgrade to a newer, faster version (like 100G Ethernet) will be possible changing only the components operating at these layers, without changing anything in the higher layers like IP and TCP, for instance.
  • This is a direct consequence of the OSI layer model foundations, that say basically that each each layer is independent from the others, so the piece of software pertaining to one layer, only interacts with his layer peer in the destination machine.
  • So, any changes to the technology used in one of the layers, don't usually affect the operation of the other layers.
3 0
3 years ago
A certain string-processing language offers a primitive operation which splits a string into two pieces. Since this operation in
Nostrana [21]

Answer:

Explanation:

First we define define cost(i,j) to be the cost of cutting the string from index i to j. Then,

cost(i,j) = min {length of substring + cost(i,k) + cost(k,j) where i < k < j}

void  s_cut()    

 {

   int l,p;

   int temp=0;

   //ArrayList<Integer> al = new ArrayList<Integer>();

   int al[];

   Scanner s=new Scanner(System.in);

   int table[][];

   ArrayList<Integer> values[][];

   int low=0,high=0;

   int min=0;

   l=s.nextInt();

   p=s.nextInt();

   System.out.println("The values are "+l+"  "+p);

   table= new int[l+1][l+1];

   values= new ArrayList[l+1][l+1];

   al= new int[p];

   for(int i=0;i<p;i++)

   {

       al[i]=s.nextInt();

   }

   for(int i=0;i<=l;i++)

   for(int j=0;j<=l;j++)

       values[i][j]=new ArrayList<Integer>();

   System.out.println();

   for(int i=1;i<=l;i++)

       table[i][i]=0;

   //Arrays.s

   Arrays.sort(al);

   for(int i=0;i<p;i++)

   {

       System.out.print(al[i]+ "  ");

   }

   for(int len=2;len<=l;len++)

   {

       //System.out.println("The length is  "+len);

       for(int i=1,j=i+len-1;j<=l;i++,j++)

       {

           high= min_index(al,j-1);

           low= max_index(al,i);

           System.out.println("Indices are "+low+"  "+high);

           if(low<=high && low!=-1 && high!=-1)

           {

           int cost=Integer.MAX_VALUE;;

           for(int k=low;k<=high;k++)

           {

               //if(al[k]!=j)

               temp=cost;

               cost=Math.min(cost, table[i][al[k]]+table[al[k]+1][j]);

               if(temp!=cost)

               {

                   min=k;  

                   //values[i][j].add(al[k]);

                   //values[i][j].addAll(values[i][al[k]]);

                   //values[i][j].addAll(values[al[k]+1][j]);

                   //values[i][j].addAll(values[i][al[k]]);

               }

               //else

               //cost=0;

           }

           table[i][j]= len+cost;

           values[i][j].add(al[min]);

           //values[i][j].addAll(values[i][al[min]]);

           values[i][j].addAll(values[al[min]+1][j]);

           values[i][j].addAll(values[i][al[min]]);

           }

           else

               table[i][j]=0;

           System.out.println(" values are "+i+"  "+j+"  "+table[i][j]);

       }

   }

   System.out.println(" The minimum cost is "+table[1][l]);

   //temp=values[1][l];

   for(int e: values[1][l])

   {

       System.out.print(e+"-->");

   }

8 0
4 years ago
Tom is trapped on the top floor of a department store. It’s just before Christmas
Artemon [7]

Answer:

tom wants to help her

Explanation:

Tom is rushing because he is at the top of a department store and he can't get a hold of her.  

5 0
3 years ago
Read 2 more answers
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