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2 years ago

What is the vertex of f(x)=x2+10x+7

Mathematics

1 answer:

Naddik [55]2 years ago

3 0

This is the answer hope this helps

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Y’all help, I have no idea what sec is or how to find it

IRINA_888 [86]

Sec is the length of the hypotenuse divided by the length of the adjacent side.

Meaning divide 20/16

Meaning your secant or sec is 1.25 or 1 1/4

7 0

3 years ago

That’s what I need to know to set it up plzzzzss help

AURORKA [14]

3×(60+7)
(3×30) + (3×7)
90 + 21 = 111

7 0

3 years ago

Read 2 more answers

Select the correct answer.

Elena L [17]

The answer is D because every number after 30 is getting multiplied by 3

4 0

3 years ago

Read 2 more answers

Researchers studying starfish collected two independent random samples of 40 starfish. One sample came from an ocean area in the

krek1111 [17]

Answer:

The test statistic for the appropriate test is $\frac{0.15-0.275}{\sqrt{0.2125(1-0.2125)[\frac{1}{40}+\frac{1}{40}]}}$ .

Step-by-step explanation:

The experiment conducted here is to determine whether there is a difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. north and south.

The hypothesis to test this can be defined as follows:

H₀: There is no difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. p₁ = p₂.

Hₐ: There is a difference in proportion of starfish over 8 inches in length in the two ocean areas, i.e. p₁ ≠ p₂.

The two-proportion z-test would be used to perform the test.

A sample of n = 40 starfishes are selected from both the ocean areas.

It provided that of the 40 starfish from the north, 6 were found to be over 8 inches in length and of the 40 starfish from the south, 11 were found to be over 8 inches in length.

Compute the sample proportion of starfish from north that were over 8 inches in length as follows:

$\hat p_{n}=\frac{6}{40}=0.15$

Compute the sample proportion of starfish from south that were over 8 inches in length as follows:

$\hat p_{s}=\frac{11}{40}=0.275$

The test statistic is:

$z=\frac{\hat p_{n}-\hat p_{s}}{\sqrt{P(1-P)[\frac{1}{n_{n}}+\frac{1}{n_{s}}]}}$

Compute the combined proportion P as follows:

$P=\frac{X_{n}+X_{s}}{n_{n}+n_{s}}=\frac{6+11}{40+40}=0.2125$

Compute the test statistic value as follows:

$z=\frac{\hat p_{n}-\hat p_{s}}{\sqrt{P(1-P)[\frac{1}{n_{n}}+\frac{1}{n_{s}}]}}$

$=\frac{0.15-0.275}{\sqrt{0.2125(1-0.2125)[\frac{1}{40}+\frac{1}{40}]}}$

Thus, the test statistic for the appropriate test is $\frac{0.15-0.275}{\sqrt{0.2125(1-0.2125)[\frac{1}{40}+\frac{1}{40}]}}$ .

8 0

3 years ago

The first term of an arithmetic sequence is -5, and the tenth term is 13. Find the common difference.

Sergeeva-Olga [200]

(A) 1.8

The difference is 18, 13 is bc the tenth term so divide 18 by 10 to get 1.8

7 0

3 years ago