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IrinaK [193]
3 years ago
13

Hi again :') i got a new question

Mathematics
2 answers:
const2013 [10]3 years ago
6 0
The answer to your question is 9 x 9 = 81.
photoshop1234 [79]3 years ago
3 0

Answer:

Nine.

Step-by-step explanation:

9 x 9 = 81.

Hope this helps!

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Can someone please help me asap !!!
vredina [299]
For this case what you should be aware of is that the root does not take negative values.
 We then have to be aware of the domain of the function.
 Note: see attached graphic.
 Ansewer
 the domain of the graph is all real number less than or equal to 0
 option 3

7 0
3 years ago
The school bus drives at 36 miles in 2 hours. If it continues at the same rate, how many miles can the bus travel in 7 hours?
jeka94

Answer: 126

Step-by-step explanation: Assuming that the bus continues at a steady rate, the bus travels 126 miles in 7 hours. One way to find this is to divide 36 by 2 to find how many miles the bus travels in 1 hour. The answer to this is 18. If you then multiply 18 by 7, you get 126. The other way to find this answer is to divide 7 hours by 2, which is 3.5; this means that the bus is traveling for 3.5 trips of 2 hours or 7 hours in total. Multiply 36 by 3.5 and you will also receive 126. Hope this helps!

8 0
3 years ago
Read 2 more answers
A polynomial function has a root of –3 with multiplicity 2, a root of 0 with multiplicity 1, a root of 1 with multiplicity 1, an
Lostsunrise [7]
We are given a polynomial function has :
A root of –3 (multiplicity 2).
Therefore, one factor would be (x+3)^2
A root of 0 with multiplicity 1.
Therefore another factor is x.
A root of 1 with multiplicity 1.
Therefore another factor is (x-1).
A root of 3 with multiplicity 2.
Therefore, another factor would be (x-3)^2
Therefore, polynomial function would
3 0
3 years ago
Which expression is the factored form of 2/3x+4
Hitman42 [59]
2/3(x+6)
2/3*x=2/3 6*2/3=4

Hope this helps :)
4 0
3 years ago
Read 2 more answers
2. (a) Use a prove by contradiction to show that if a and b are nonzero integers such that a divides b and a + b is odd, then a
devlian [24]

a. Assume a is even, so a = 2k for some integer k. Now let a and b be integers such that a divides b and a + b is odd.

Since a divides b, b = an for integer n, and in turn b = 2nk, which means <u>b is even</u> and hence a + b is also even. But this contradicts our initial assumption, so a must be odd.

b. Let n be even, so that n = 2k for some integer k. Then

n² = (2k)² = 4k²

so that n² ≡ 0 (mod 4).

Now let n be odd, so n = 2k + 1 for integer k. Then

n² = (2k + 1)² = 4k² + 4k + 1

so that n² ≡ 1 (mod 4).

Therefore n² is never congruent to 2 (mod 4).

4 0
3 years ago
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