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kolezko [41]
3 years ago
5

What the square root of 2000

Mathematics
1 answer:
Rudik [331]3 years ago
7 0

Answer:

44.7213595

Step-by-step explanation:

I need to write something here apparently

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Keith is racing his little sister Pattie and has given her a 15 foot head start. She runs 5ft/sec and he is chasing at 8ft/sec.
hodyreva [135]
Pattie runs at 5 ft/sec
She has got a head start of 15 feet.
So after 1 second, Pattie runs = (5+15) ft <span>                                                   
                                                  = 20 </span> ft
After 2 second Pattie runs = (20+5)ft
                                           = 25 ft
After 3 second Pattie runs = (25+5) ft
                                           = 30 ft
After 4 seconds Pattie runs = (30+5) ft
                                             = 35 ft
After 5 seconds Pattie runs = (35+5) ft
                                             = 40 ft
After 6 seconds Pattie runs  = (40+5) ft
                                             = 45 ft
Now Keith runs at 8 ft/sec
After 1 second Keith runs = 8 ft
After 2 second Keith runs = (8+8) ft
                                           = 16 ft
After 3 second Keith runs = (16+8) ft
                                           = 24 ft
After 4 second Keith runs = (24+8) ft
                                          = 32 ft
After 5 second Keith runs = (32+8) ft
                                           = 40 ft
After 6 second Keith runs = (40+8) ft
                                           = 48 ft
So Pattie will stay ahead of Keith upto 4 seconds. In the 5th second Pattie and Keith will be level and in the 6th second Pattie will be overtaken by Keith.


8 0
4 years ago
In ΔNOP, \overline{NP} NP is extended through point P to point Q, \text{m}\angle PNO = (x+14)^{\circ}m∠PNO=(x+14) ∘ , \text{m}\a
adelina 88 [10]

Answer:

<OPQ = 23 degrees

Step-by-step explanation:

Given

Interior angles m∠PNO=(x+14) and m∠NOP=(x−1)

Exterior angle = m<OPQ = (5x-2)

The sum of interior angles is equal to the exterior angle, that is;

m∠PNO+m∠NOP = m<OPQ

x+14 + x-1 = 5x-2

2x + 13 = 5x-2

Collect like terms;

2x-5x = -2-13

-3x = -15

x = 15/3

x = 5

Get <OPQ

<OPQ = 5x - 2

<OPQ = 5(5)- 2

<OPQ = 25-2

<OPQ = 23 degrees

4 0
3 years ago
Use your graph to estimate solutions to the equation x2-2x-1=0
garri49 [273]

There are 2 real solutions to the equation.  Evaluate  the discriminant = 8.             Using the quadratic formula = What is on the picture.

3 0
3 years ago
Casey is completing an experiment that requires 300 mL of potassium chloride (KCl) at a concentration of 0.2 M. But Casey's lab
gulaghasi [49]
What you first need to do is make an equation. Then plug that equation into photomath and you get your answer


3 0
3 years ago
ALGEBRA 1, SEMESTER 2
SIZIF [17.4K]

So firstly, we have to find f(x) when x = 8 and x = 0. Plug the two numbers into the x variable of the function to solve for their f(x):

f(0)=\frac{2*0+3}{3*0-3}\\ f(0)=\frac{0+3}{0-3}\\ f(0)=\frac{3}{-3}\\ f(0)=-1\\ \\ f(8)=\frac{2*8+3}{3*8-3}\\ f(8)=\frac{16+3}{24-3}\\ f(8)=\frac{19}{21}

Now that we have their y's, we can use the slope, aka average rate of change, formula, which is \frac{y_2-y_1}{x_2-x_1} . Using what we have, we can solve it as such:

\frac{\frac{19}{21}-(-1)}{8-0}=\frac{\frac{40}{21}}{8}=\frac{40}{21*8}=\frac{40}{168}=\frac{5}{21}

In short, the average rate of change from x = 0 to x = 8 is 5/21.

8 0
3 years ago
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