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2 years ago

Asher is asked to find the factors of 10. His work is below.

Mathematics

1 answer:

Assoli18 [71]2 years ago

5 0

Answer:

B and D

Step-by-step explanation:

<u>Answer choices:</u>

A) Asher made errors in multiplication.

No, the products are correct

B) Asher found multiples of 10, not factors of 10.

C) Asher should have multiplied 10 × 4 as well.

No, 4 is not one of the factors of 10

D) Asher should have gotten this as the answer: 1, 2, 5, and 10.

Yes, these are the true factors of 10

E) Asher should have gotten this as the answer: 10, 20, 30, 40, …

No, the correct one is one before

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A factory received a shipment of 11 hammers, and the vendor who sold the items knows there are 2 hammers in the shipment that ar

zhenek [66]

Question:

If a sample of 2 hammer is selected

(a) find the probability that all in the sample are defective.

(b) find the probability that none in the sample are defective.

Answer:

a $Pr = \frac{2}{110}$

b $Pr = \frac{72}{110}$

Step-by-step explanation:

Given

$n = 11$ --- hammers

$r = 2$ --- selection

This will be treated as selection without replacement. So, 1 will be subtracted from subsequent probabilities

Solving (a): Probability that both selection are defective.

For two selections, the probability that all are defective is:

$Pr = P(D) * P(D)$

$Pr = \frac{2}{11} * \frac{2-1}{11-1}$

$Pr = \frac{2}{11} * \frac{1}{10}$

$Pr = \frac{2}{110}$

Solving (b): Probability that none are defective.

The probability that a selection is not defective is:

$P(D') = \frac{9}{11}$

For two selections, the probability that all are not defective is:

$Pr = P(D') * P(D')$

$Pr = \frac{9}{11} * \frac{9-1}{11-1}$

$Pr = \frac{9}{11} * \frac{8}{10}$

$Pr = \frac{72}{110}$

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3 years ago

What is the sst for the data set (1,5),(2,8),(4,14)?

monitta

Answer: 42 (apex)

Step-by-step explanation:

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3 years ago

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The graph of $y = ax^2 + bx + c$ is shown below. Find $a \cdot b \cdot c$. (The distance between the grid lines is one unit.)

Savatey [412]

Answer:

$a\cdot b\cdot c=\frac{15}{4}$

Step-by-step explanation:

Vertex is the minimum or maximum point of parabola

Vertex of parabola is (h,k)

Therefore, from given graph (-3,-2) is the lowest point.

Vertex of parabola is at (-3,-2).

Standard equation of parabola

$y-k=a(x-h)^2$

Substitute the values

$y-(-2)=a(x-(-3))^2=a(x+3)^2$

$y+2=a(x+3)^2$

(-1,0) lies on the parabola.

Therefore, it satisfied the equation of parabola.

$0+2=a(-1+3)^2=4a$

$a=2/4=1/2$

Now, using the value of a

$y+2=1/2(x+3)^2=1/2(x^2+6x+9)$

$y+2=\frac{1}{2}x^2+3x+\frac{9}{2}$

$y=\frac{1}{2}x^2+3x+\frac{9}{2}-2$

$y=\frac{1}{2}x^2+3x+\frac{9-4}{2}$

$y=\frac{1}{2}x^2+3x+\frac{5}{2}$

By comparing with

$y=ax^2+bx+c$

We get

$a=\frac{1}{2}, b=3, c=5/2$

$a\cdot b\cdot c=\frac{1}{2}\times 3\times \frac{5}{2}$

$a\cdot b\cdot c=\frac{15}{4}$

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2 years ago

Does 4/3 terminate or repeat?

Mars2501 [29]

Step-by-step explanation:

terminate as it had already been simplify

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3 years ago

Your housing and fixed expenses are $685.70/month. If they are 33% of your realized income, how much is your realized income per

galben [10]

$685.70÷33%=$2,077.88
A

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3 years ago

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