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2 years ago

Really easy please help me

Mathematics

2 answers:

natka813 [3]2 years ago

5 0

Need a picture or a problem then we can help

DIA [1.3K]2 years ago

4 0

We need a picture, then we can help you with the problem.

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Can someone answer this question please WBA’s wee it correctly if it’s correct I will mark you brainliest

oksano4ka [1.4K]

Answer:

$\frac{1}{6}*\frac{4}{13}$

Step-by-step explanation:

A 6 sided die has 6 outcomes.

Your sister picks from a 13 - slice plate meaning the fact that there are 13 outcomes.

There are 4 yellow slices so picking a yellow slice has a $\frac{4}{13}$ chance

You need to mutiply both displayed values to solve this problem.

$\frac{1}{6}*\frac{4}{13}$

6 0

2 years ago

PLS HELLP PLS PLS

Andrew [12]

Answer:

it would be 100 rounded because 14x8=112 and 112 is rounded to 100 to the nearest hundreth. Please subscribe to Amiredagoat Yt

Step-by-step explanation:

6 0

2 years ago

What is the mean of these numbers ? <br> 2,8,4,6,5

MrRa [10]

Answer:

5 is the mean

Step-by-step explanation:

4 0

2 years ago

At the building site there are 16 pallets with sacks of cement the total weight of all the pallets and cement is 4856 pounds eac

inysia [295]

The first thing we must do for this case is to define a variable.
We have then:
x: weight of each pallet with cement
We then have the following equation:
16x = 4856
Clearing x we have:
x = (4856) / (16)
x = 303.5 punds
Answer:
each pallet with cement weigh:
x = 303.5 punds

6 0

2 years ago

The average score of all pro golfers for a particular course has a mean of 70 and a standard deviation of 3.0 (Think of these as

bija089 [108]

Answer:

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 70

Standard Deviation, σ = 3

Sample size, n = 36

Let the average score of all pro golfers follow a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(score of the 36 golfers was between 70 and 71)

$\text{Standard error of sampling} = \displaystyle\frac{\sigma}{\sqrt{n}} = \frac{3}{\sqrt{36}} = \frac{1}{2}$

$P(70 \leq x \leq 71) = P(\displaystyle\frac{70 - 70}{\frac{3}{\sqrt{36}}} \leq z \leq \displaystyle\frac{71-70}{\frac{3}{\sqrt{36}}}) = P(0 \leq z \leq 2)\\\\= P(z \leq 2) - P(z \leq 0)\\= 0.977 - 0.500 = 0.477= 47.7\%$

$P(70 \leq x \leq 71) = 47.7\%$

0.477 is the probability that the average score of the 36 golfers was between 70 and 71.

8 0

3 years ago