If a large shake uses 8/9 pint of milk and a medium 1/7 of the amount of the large how much does the medium take?

Arada [10]

M/_b = 90-55=35°......

5 0

3 years ago

A report includes a statement that the "average" test score of applicants to medical schools is 28.4. What is the role of the t

qaws [65]

Answer:

See explanation below.

Step-by-step explanation:

The average is measure of central tendency that is also called sample mean and is calculated from the following formula:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

This is an estimator of the population mean and is unbiased since the expected value for the estimator is the same parameter as we can see here:

$E(\bar X)=\frac{\sum_{i=1}^n E(X_i)}{n} =\frac{n\mu}{n}=\mu$

And is important because is the most common measure of central tendency reported on any study.

Is important to remember that this measure can be affected by outliers , for this case when we have outliers is better use the median as a measure of central tendency

7 0

3 years ago

Operations with Radical Expressions

lisov135 [29]

Answer: $30\sqrt{11}$

Step-by-step explanation:

$3\sqrt{50} * \sqrt{22}$

= $3\sqrt{5*5*2} * \sqrt{2*11}$

= $3\sqrt{5*5*2*2*11}$

= $3*5*2\sqrt{11}$

= $30\sqrt{11}$

******************************************

Answer: $6\sqrt{30}$

Step-by-step explanation:

$\sqrt{20} * \sqrt{3} * \sqrt{18}$

= $\sqrt{2*2*5} * \sqrt{3} * \sqrt{3*3*2}$

= $\sqrt{2*2*5*3*3*3*2}$

= $2*3\sqrt{5*3*2}$

= $6\sqrt{30}$

********************************************

Answer: $-\sqrt{5}$

Step-by-step explanation:

$4\sqrt{20} - 3\sqrt{45}$

= $4\sqrt{2*2*5} - 3\sqrt{3*3*5}$

= $4*2\sqrt{5} - 3*3\sqrt{5}$

= $8\sqrt{5} - 9\sqrt{5}$

= $-\sqrt{5}$

********************************************

Answer: $4\sqrt{5}$

Step-by-step explanation:

$2\sqrt{5} + 3\sqrt{5} - \sqrt{5}$

= $(2+3-1)\sqrt{5}$

= $4\sqrt{5}$

********************************************

Answer: $46\sqrt{2}$

Step-by-step explanation:

$4\sqrt{32} + 6\sqrt{50}$

= $4\sqrt{2*2*2*2*2} + 6\sqrt{2*5*5}$

= $4*2*2\sqrt{2} + 6*5\sqrt{2}$

= $16\sqrt{2} + 30\sqrt{2}$

= $46\sqrt{2}$

7 0

3 years ago

Power +, Inc. produces AA batteries used in remote-controlled toy cars. The mean life of these batteries follows the normal prob

Novay_Z [31]

Answer:

a) By the Central Limit Theorem, it is approximately normal.

b) The standard error of the distribution of the sample mean is 1.8333.

c) 0.1379 = 13.79% of the samples will have a mean useful life of more than 38 hours.

d) 0.7939 = 79.39% of the samples will have a mean useful life greater than 34.5 hours

e) 0.656 = 65.6% of the samples will have a mean useful life between 34.5 and 38 hours

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 36 hours and a standard deviation of 5.5 hours.

This means that $\mu = 36, \sigma = 5.5$

a. What can you say about the shape of the distribution of the sample mean?

By the Central Limit Theorem, it is approximately normal.

b. What is the standard error of the distribution of the sample mean? (Round your answer to 4 decimal places.)

Sample of 9 means that $n = 9$ . So

$s = \frac{\sigma}{\sqrt{n}} = \frac{5.5}{\sqrt{9}} = 1.8333$

The standard error of the distribution of the sample mean is 1.8333.

c. What proportion of the samples will have a mean useful life of more than 38 hours?

This is 1 subtracted by the pvalue of Z when X = 38. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{38 - 36}{1.8333}$

$Z = 1.09$

$Z = 1.09$ has a pvalue of 0.8621

1 - 0.8621 = 0.1379

0.1379 = 13.79% of the samples will have a mean useful life of more than 38 hours.

d. What proportion of the sample will have a mean useful life greater than 34.5 hours?

This is 1 subtracted by the pvalue of Z when X = 34.5. So

$Z = \frac{X - \mu}{s}$

$Z = \frac{34.5 - 36}{1.8333}$

$Z = -0.82$

$Z = -0.82$ has a pvalue of 0.2061.

1 - 0.2061 = 0.7939

0.7939 = 79.39% of the samples will have a mean useful life greater than 34.5 hours.

e. What proportion of the sample will have a mean useful life between 34.5 and 38 hours?

pvalue of Z when X = 38 subtracted by the pvalue of Z when X = 34.5. So

0.8621 - 0.2061 = 0.656

0.656 = 65.6% of the samples will have a mean useful life between 34.5 and 38 hours

4 0

3 years ago

What is 689 divided by 24

ozzi

28.7083333333...
But you could also round it up to 29.

3 0

3 years ago