Answer:
Inequality: x + 4 ≥ 12
Solution: x ≥ 8
Step-by-step explanation:
<u>Plus</u>: "+" → to add something to something else
<u>Greater than or equal to</u>: "≥" → the expression on the left side of the inequality sign is greater than the expression on the right side of the sign.
Let x be the unknown number.
A number plus four is greater than or equal to twelve:
x + 4 ≥ 12
To solve the found inequality, subtract 4 from both sides:
⇒ x + 4 - 4 ≥ 12 - 4
⇒ x ≥ 8
Therefore, the solution to the inequality is x ≥ 8. The unknown number x can be any real number equal to or greater than 8.
<span>f(q) = 2q + 3
The first one says the function of q, but does not actually use q as a variable. You would want q to be the variable if the function is of q. </span>
Answer:
We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.
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Explanation:
It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.
I'm going to use these three log rules, which apply to any base.
- log(A) + log(B) = log(A*B)
- log(A) - log(B) = log(A/B)
- B*log(A) = log(A^B)
From there, we can then say the following: