<u>ANSWER</u>
A. (4,12)
<u>EXPLANATION</u>
The equations are:
![10x +2y = 64...(1)](https://tex.z-dn.net/?f=10x%20%2B2y%20%3D%2064...%281%29)
and
![3x - 4y = -36...(2)](https://tex.z-dn.net/?f=3x%20-%204y%20%3D%20-36...%282%29)
To eliminate a variable we make the coefficients of that variable the same in both equations.
It is easier to eliminate x.
We multiply the first equation by 2 to get:
![20x + 4y = 128...(3)](https://tex.z-dn.net/?f=20x%20%2B%204y%20%3D%20128...%283%29)
We add equations (2) and (3).
![3x + 20x + 4y - 4y = - 36 + 128](https://tex.z-dn.net/?f=3x%20%2B%2020x%20%2B%204y%20-%204y%20%3D%20%20-%2036%20%2B%20128)
![23x = 92](https://tex.z-dn.net/?f=23x%20%3D%2092)
Divide both sides by 23
![\frac{23x}{23} = \frac{92}{23}](https://tex.z-dn.net/?f=%20%5Cfrac%7B23x%7D%7B23%7D%20%20%3D%20%20%5Cfrac%7B92%7D%7B23%7D%20)
![x = 4](https://tex.z-dn.net/?f=x%20%3D%204)
Put x=4 into equation (1).
![10(4)+2y = 64](https://tex.z-dn.net/?f=10%284%29%2B2y%20%3D%2064)
![40+2y = 64](https://tex.z-dn.net/?f=40%2B2y%20%3D%2064)
![2y = 64 - 40](https://tex.z-dn.net/?f=2y%20%3D%2064%20-%2040)
![2y = 24](https://tex.z-dn.net/?f=2y%20%3D%2024)
![\frac{2y}{2} = \frac{24}{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2y%7D%7B2%7D%20%20%3D%20%20%5Cfrac%7B24%7D%7B2%7D%20)
![y = 12](https://tex.z-dn.net/?f=y%20%3D%2012)
The solution is (4,12)
12 4/5 can be changed as 64/5 so there are 64 1/5ths
Answer: -8
Step-by-step explanation:
if y=6x+(-2), than y= 6x-2
if x=-1 we will replace x with this value
y=6(-1)-2=-6-2=-8
Answer:
Step-by-step explanation:
The ratio of its areas is equal to
Step-by-step explanation:
we know that
If two figures are similar, then the ratio of its areas is equal to the scale factor squared
In this problem the scale factor is equal to the ratio 10:3
Let
z-------> the scale factor
so
z2=(10/3)2=100/9
Answer:
y=-8/5x+77/5
Step-by-step explanation:
The equation of line that passes through the points (4, 9) and (9, 1) is y=-8/5x+77/5. Hope it helps!