What is the length of JL?

Mathematics

2 answers:

Xelga [282]3 years ago

8 0

8 units/ first answer

BaLLatris [955]3 years ago

4 0

Answer: 8 Units

btw have a good day :)

You might be interested in

Hurryyyyy pleaseeee.

Black_prince [1.1K]

Answer:

$4 \times \frac{9}{16}$

Step-by-step explanation:

$3 + (2 + 8) ^{2} \div 4 \times ( \frac{1}{2})^{4}$

$3 + 10 ^{2} \div 4( \frac{1}{16} ) \\ 3 + \frac{10 ^{2} }{4} \times \frac{1}{16} \\ 3 + \frac{100}{4} \times \frac{1}{16} \\ 3 + 25 \times \frac{1}{16} \\ 3 + \frac{25}{16} \\ \frac{73}{16}$

In mixed number form it is

$4 \times \frac{9}{16}$

8 0

4 years ago

Find the gradient of the tangent to the curve y = 5x³ + 3x² - x + 4

Luba_88 [7]

The gradient of the tangent to the curve y = 5x³ + 3x² - x + 4 is 15x²+6x-1.

<h3>What is the gradient?</h3>

A differential operator is used for a function having a vector value in three dimensions to produce a vector whose three components are the partial derivatives of the function with respect to its three variables.

The given equation for the curve is;

y = 5x³ + 3x² - x + 4

The gradient of the tangent to the curve is;

$\rm y'=\frac{dy}{dx} \\\\ y'= 5x^3 + 3x^2- x + 4 \\\\\ y'=15x^2+6x-1$