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saveliy_v [14]
3 years ago
15

What is the surface area of this triangle prism

Mathematics
1 answer:
k0ka [10]3 years ago
8 0
Is there a picture along with the question
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Help me again please <br> 2(36-4t) t= 3.4
olasank [31]
Since we know that t = 3.4 you put 3.4 where the t is.

2 (36 - 4 × 3.4) So what you do first is multiply 4 and 3.4 which gives you 13.6

2 (36 - 13.6) then you subtract 36 and 13.6 which gives you 22.4

2 (22.4) then you multiply 2 and 22.4 which is 44.8.

So your answer is 44.8

I hope that helped!
3 0
3 years ago
Restaurant Revenue
Fittoniya [83]

Answer:

The cost per costumer is 10 + x

Step-by-step explanation:

I hope this helps! :)

5 0
3 years ago
What operations do I use when it says a number 3 times as much as another
kupik [55]

multiply the number three times by the other number.

7 0
3 years ago
What is the value of x?
Nataly [62]
4x+2=5x-6
4x-5x=-6-2
-x=-8
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6 0
3 years ago
Read 2 more answers
Suppose that, in addition to edge capacities, a flow network has vertex capacities. That is each vertex has a limit l./ on how m
storchak [24]

Answer:

See explanation and answer below.

Step-by-step explanation:

The tranformation

For this case we need to construct G' dividing making a division for each vertex v of G into 3 edges that on this case are v_1, v_2 and l(v).

We assume that the edges from the begin are the incoming edges of v_1 and all the outgoing edges from v are outgoing edges from v_2

We need to construct G' = (V', E') with capacity function a' and we need to satisfy the follwoing:

For every v \in V we create 2 vertices v_1, v_2 \in V'

Now we can add a new edge asscoiated to v_1, v_2 \in E' with the condition a' (v_1,v_2) = l(v)

Now for each edges (u,v)\in E we can create the following edge ( u_r, v_1) \in E' and the capacity is given by: a' (u_r, v_1) = a (u,v)

And for this case we can see this:

|V'| = 2|V|, |E'|= |E| +|V|

Now we assume that x is the flow who belongs to G respect vertex capabilities. We can create a flow function x' who belongs to G' with the following steps:

For every edge (u,v) \in G we can assume that x' (u_r ,v_1) = x(u,v)

Then for each vertex u \in V -t and we can define x\(u_1,u_r) = \sum_{v \in V} x(u,v) and x' (t_1,t_2) = \sum_{v \in V} x(v,t)

And after see that the capacity constraint on this case would be satisfied since for every edge in G' on the form (u_r, u_1) we have a corresponding edge in G because:

u \in V -(s,t) we have that:

x' (u_1, u_r) = \sum_{v \in V} x(u,v) \leq l(u) = a' (u_1, u_r)

x' (t_1,t_2) = \sum_{v \in V} x(v,t) \leq (t) = a' (t_1,t_2)

And with this we have the maximization problem solved.  

We assume that we have K vertices using the max scale algorithm.

6 0
3 years ago
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