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2 years ago

Can someone help me. i dont know what's the answer.

Mathematics

1 answer:

n200080 [17]2 years ago

5 0

Answer: i think it’s 276
explanation: i think i counted all the sides i’m not sure tho, i hope it’s right. good luck:)

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The ten students in a club are lined up in a row for a group photograph. How many different arrangements are possible if the clu

kondor19780726 [428]

We know that

if the club includes one set of identical triplets wearing matching clothes

then

the number of different arrangements that are possible is

10! / 3! = (10*9*8*7*6*5*4*3!)/3!

=604,800

The answer is

8 0

3 years ago

Read 2 more answers

Karen Sullivan delivers newspapers for the Tribune dispatch. She receives 18.2 cents per paper, six days a week (for the daily p

mario62 [17]

Answer:

About $241.11

Step-by-step explanation:

So, Karen receives 18.2 cents per paper.

She delivers 124 paper per day.

In other words, on days other than Sunday, she will make a total of:

$18.2(124)=2256.8\text{ cents}$

On Sunday, each paper is sold for $0.70 or 70 cents. She also sells 151 Sunday papers. Thus, on a Sunday, she will make a total of:

$70(151)=10570\text{ cents}$

Therefore, in one week, she will do the first equation six times and the Sunday equation once. Thus, her total pay will be:

$6(2256.8)+10570=24110.8\text{ cents}\approx\$241.11$

4 0

3 years ago

Use the listing method to represent the following set.

Hatshy [7]

Answer:

Step-by-step explanation:

{x | x I, x ≥ 3}

6 0

3 years ago

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I REALLY NEED HELP!!!

valkas [14]

Answer:

Oh naw i can't help you with that one man but thanks for the points 63567Step-by-step explanation:

b 674 then38743 then 8391

7 0

2 years ago

Read 2 more answers

What is the LCM of 13/16a^3b^3, 11/30a^5b

vichka [17]

Answer:

The L.C.M of given numbers is $\frac{143}{240}a^5b^3$ .

Step-by-step explanation:

The given expressions are

$\frac{13}{16}a^3b^3$

$\frac{11}{30}a^5b$

The factors of given expressions are

$\frac{13}{16}a^3b^3=\frac{13}{8}\times \frac{1}{2}\times a\times a\times a\times b\times b\times b$

$\frac{11}{30}a^5b=\frac{11}{15}\times \frac{1}{2}\times a\times a\times a\times a\times a\times b$

$L.C.M.=\frac{13}{8}\times \frac{1}{2}\times a\times a\times a\times b\times b\times b\times \frac{11}{15}\times a\times a$

$L.C.M.=\frac{143}{240}\times a^5\times b^3$

$L.C.M.=\frac{143}{240}a^5b^3$

Therefore, the L.C.M of given numbers is $\frac{143}{240}a^5b^3$ .

8 0

3 years ago