Solving a system of equations, we will see that there are 6000 kg of coal on the pile.
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How many kilograms of coal are in the pile of coal?</h3>
Let's say that there are N kilograms of coal, and it is planned to burn it totally in D days, these are our variables.
We know that:
- If the factory burns 1500 kilograms per day, it will finish burning the coal one day ahead of planned.
- If it burns 1000 kilograms per day, it will take an additional day than planned.
Then we can write the system of equations:
(1500)*(D - 1) = N
(1000)*(D + 1) = N
Because N is already isolated in both sides, we can write this as:
(1500)*(D - 1) = N = (1000)*(D + 1)
Then we can solve for D:
(1500)*(D - 1) = (1000)*(D + 1)
1500*D - 1500 = 1000*D + 1000
500*D = 2500
D = 2500/500 = 5
Now that we know the value of D, we can find N by replacing it in one of the two equations:
(1500)*(D - 1) = N
(1500)*(5 - 1) = N
(1500)*4= N = 6000
This means that there are 6000 kilograms of coal on the pile.
If you want to learn more about systems of equations:
brainly.com/question/13729904
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Here is the set up:
Let x and y be the two numbers with x the smaller and y the larger number.
x + y = 66
2x = y + 15
We have two equations in two unknowns.
Take it from here.
You can fir 8x8x8 cubes in the carton, that means you can fit 512 cubes in the carton.
the total cost would be, 0.25 x 512 = $128
If the length is taken as l , height is taken as h and breadth is taken as b . then
Area of the rectangular prism= 2( (l*b) + (b*h) + (h*l) )
hope that helps
Answer:
X≤3
Step-by-step explanation:
This is because the arrow is moving down the number line
