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3 years ago

Erica says that 1/5 of the national flag of Thailand shown on the right is blue. what’s wrong?

Mathematics

1 answer:

Angelina_Jolie [31]3 years ago

3 0

Answer:

The blue portion of the flag is actually 2/6 or 1/3 of the flag

Step-by-step explanation:

If you look at the size of the blue portion of the line it takes up twice the space as the white part. Imagine a small line drawn through the middle of the blue rectangle, now you can see that the flag is split up into 6 parts, rather then 5! Since we now have 2/6 of the flag being taken up by blue, that can be reduced down to 1/3 of the flag covered in blue.

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Which expression is equivalent ?<br><br> LOOK AT THE PICTURE

victus00 [196]

Answer:

x^ (5/3) y ^ 1/3

Step-by-step explanation:

Rewriting as exponents

(x^5y) ^ 1/3

We know that a^ b^c = a^(b*c)

x^ (5/3) y ^ 1/3

8 0

4 years ago

Read 2 more answers

Write an equation for the translation of y = |x|. 13 units down

olga55 [171]

The idea for transitions for an equation like this is
$y = m|x - h| + k$
where m = slope
h = how much left or right (note the negative)
k = how much up or down

moving 13 down would mean
k = -13

so
$y = |x| - 13$
D. would be your answer

7 0

3 years ago

Using the traditional formula, a 95% CI for p1 − p2 is to be constructed based on equal sample sizes from the two populations. F

inn [45]

Answer:

Step-by-step explanation:

Given:

Width = 0.4

Let's take the z value of 95% which is = 1.96

Let's assume population proportion p1 and p2 = 0.5

For margin of error E, the relation between the width and margin of error is 2E.

i.e 2E = 0.4

E = 0.2

To find the sample size, n, let's use the formula :

$n= \frac{z^2*(p_1(1-p_1) + p_2(1-p_2))}{E^2}$

$= \frac{1.96^2(0.5(1-0.5)+0.5(1-0.5))}{0.2^2}$

= 48.02

≈ 49

8 0

3 years ago

PLEASEE HELP!

melamori03 [73]

Answer:

Two non zero vectors, a and b are parallel when they are scalar multiples of each other such that a = c·b where c is a scalar quantity.

Therefore, in order to find a vector that is parallel to the vector, b = (-2, -1), we multiply the vector, b by a scaler quantity

Step-by-step explanation:

Given that the vector b = (-2, -1) can be written as follows;

b = -2·i - j, we have;

$\left | b \right |$ = √((-2)² + (-1)²) = √5

Therefore, we have;

The coordinates of the endpoint of the vector are (-2, 0) and (0, -1)

Therefore, the slope of the vector = (-1 - 0)/(0 - (-2)) = -1/2

The slope of parallel vectors are equal, which gives the slope of the parallel vector = -1/2 = (λ × (-1 - 0))/(λ ×(0 - (-2))

Therefore, a parallel vector is obtained from a vector by multiplying with a scaler product.

7 0

3 years ago

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$

Hence, probability of the stronger team winning overall is:

$=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103$

#Define Y as the random variable for winning 2/3 games.:

$P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480$

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0

3 years ago