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GuDViN [60]
2 years ago
7

Find x and explain how you found it!

Mathematics
2 answers:
Lerok [7]2 years ago
5 0

Answer:

\Large\boxed{\sf x = 19.2}

Step-by-step explanation:

Here a right angled triangle is given to us and we need to find out the value of x . The measure of one of the sides is 24 and one of the acute angle is 53° .

  • Here 24 is hypotenuse of the triangle and x is the perpendicular .

So here we may use the ratio of sine as ,

\sf\qquad\longrightarrow sin\theta =\dfrac{p}{h}  \\\\

<u>•</u><u> </u><u>On</u><u> </u><u>substitut</u><u>i</u><u>n</u><u>g</u><u> </u><u>the</u><u> </u><u>respective</u><u> </u><u>values</u><u> </u><u>,</u>

\sf\qquad\longrightarrow  sin53^\circ =\dfrac{x}{24}\\\\

Substitute the value of sin 53° = 4/5 ,

\sf\qquad\longrightarrow \dfrac{4}{5}=\dfrac{x}{24} \\\\

Cross multiply ,

\sf\qquad\longrightarrow x =\dfrac{24*4}{5}  \\\\

Simplify,

\sf\qquad\longrightarrow \frak{\pink{x =19.2}} \\\\

\rule{200}4

Doss [256]2 years ago
4 0

Here we use trigonometric ratios

\\ \rm\hookrightarrow sin\theta=\dfrac{Perpendicular}{Hypotenuse}

\\ \rm\hookrightarrow sin53=\dfrac{x}{24}

\\ \rm\hookrightarrow 0.8(24)=x

\\ \rm\hookrightarrow x=19.2

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